Chemistry

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New answer posted

8 months ago

0 Follower 14 Views

P
Payal Gupta

Contributor-Level 10

λt=lnNoNt

0.693t1/2*t=ln1Nt

Or 0.693*10030=ln1Nt

1Nt=10

Nt=110=0.1

Or Nt = 1 * 101 μg

New answer posted

8 months ago

0 Follower 3 Views

P
Payal Gupta

Contributor-Level 10

ΔTf=Kf*m

(156155.1)=2*1.8MW*1000 (62.5*0.8)

0.9 = 2*1.8*1000MW*50

MW=80gm/mol

New answer posted

8 months ago

0 Follower 14 Views

P
Payal Gupta

Contributor-Level 10

Following have the sp3d2 hybridisation

New answer posted

8 months ago

0 Follower 6 Views

P
Payal Gupta

Contributor-Level 10

Po2 = PTotalPN2

= 25 – 20 = 5bar

Po2nO2nO2+nNe*PTotal

5= (x/32x/32+20020)*25x=80gm

New question posted

8 months ago

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New answer posted

8 months ago

0 Follower 13 Views

P
Payal Gupta

Contributor-Level 10

 ΔH=165kJ/mole

T =?

ΔS=550JK1

At equilibrium ; ΔG=0

T=ΔHΔS=165*1000550K

=3*100K=300K

New answer posted

8 months ago

0 Follower 58 Views

P
Payal Gupta

Contributor-Level 10

E1H=2.2*1018J

LiLi+2+2e, n=2

ELi+2=E1H*Z2n2=2.2*1018*3222

λ=4*108 m

New answer posted

8 months ago

0 Follower 3 Views

P
Payal Gupta

Contributor-Level 10

d=ZMNAa3=4*58.56.02*1023*a3

43.1=4*58.56.02*1023*a3

a=2.08*108cm

rNa++rCl=1.04*1010 m

New answer posted

8 months ago

0 Follower 9 Views

P
Payal Gupta

Contributor-Level 10

Molar mass of C7H5N3O6 = 12 * 7 + 1 * 5 + 14 * 3 + 16 * 6 = 84 + 42 + 96 = 227 g/mol

Number of moles = 6 8 1 2 2 7  = 3 mol

number of N-atoms

=3*6.02*1023*3=9*6.02*1023

=5418*1021

x=5418         

New answer posted

8 months ago

0 Follower 4 Views

V
Vishal Baghel

Contributor-Level 10

% of C in organic compound

= 1 2 1 4 * W C O 2 W . O . C . * 1 0 0

= 9 5 2 . 5 6 2 1 . 6 4 8 = 4 4 %

% o f H = 2 1 8 * W H 2 O W . O . C . * 1 0 0

= 2 0 1 8 * 0 . 4 4 2 8 0 . 4 9 2 * 1 0 0

= 8 8 . 5 6 8 . 8 5 6 = 1 0 %

= 100 – 54 = 46%

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