Chemistry

Get insights from 6.9k questions on Chemistry, answered by students, alumni, and experts. You may also ask and answer any question you like about Chemistry

Follow Ask Question
6.9k

Questions

0

Discussions

22

Active Users

0

Followers

New answer posted

a year ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

Balmer series lies in the visible region.

New answer posted

a year ago

0 Follower 7 Views

A
alok kumar singh

Contributor-Level 10

Reactivity towards AgNO3 depend on stability of carbocation formed

 

New answer posted

a year ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

(a) In extraction of iron lime stone is added on a flux

CaCO3? CaO+CO2CO2+SiO2? CaSiO3

(b) Extraction of silver

Ag+NaCN?  anionic complex Ag (CN)2-

(c) Nickel is purified by Mond's process

(d) Zr and Ti are purified by Van Arkel method by converting to volatile iodide.

New answer posted

a year ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

Organic compound → AgBr (s)

      0.5 g  0.40 g

Here; Moles of Br in organic compound = Moles of Br in Ag Br

= Moles of AgBr

= 0.40188mol

Mass of Br in organic compound = 0.4188*80g

%  of  Br=0.4*80188*0.5*100%=34%

New answer posted

a year ago

0 Follower 4 Views

P
Payal Gupta

Contributor-Level 10

All metal carbonyls have synergic bonds.

New answer posted

a year ago

0 Follower 6 Views

P
Payal Gupta

Contributor-Level 10

Rate constant, k = 5.5 * 10-14 s-1.

t = 2 . 3 0 3 k l o g [ R ] 0 [ R ]                

= 2 . 3 0 3 k l o g 3 − ( i )  

t 5 0 % = 2 . 3 0 3 k l o g 2 − ( i i )                

From (i) & (ii)

t 6 7 % t 5 0 % = l o g 3 l o g 2                

= 1.58 t50%

So; t67% is 15.8 * 10-1 times half life.

X = 16 (the nearest integer)

New answer posted

a year ago

0 Follower 3 Views

P
Payal Gupta

Contributor-Level 10

C r 2 O 7 2 − + 6 e − + 1 4 H + → 2 C r 3 + + 7 H 2 O  

Here, 6F electricity is required to reduce 1 mol  C r 2 O 7 2 − to Cr3+.

New answer posted

a year ago

0 Follower 8 Views

P
Payal Gupta

Contributor-Level 10

Using ; ksp = 108 S5

1.1 * 10-23 = 108 S5

S = ( 1 1 0 1 0 8 * 1 0 − 2 5 ) 1 / 5 M ≈ 1 0 − 5 M  

Specific conductance,

λ m 0 = κ 5 * 1 0 0 0 S m 2 m o l − 1                              

= 3 * 10-3 Sm2 mol-1

So; x = 3

New answer posted

a year ago

0 Follower 4 Views

P
Payal Gupta

Contributor-Level 10

P A 0 = 5 0     t o r r

P B 0 = 1 0 0     t o r r

Mole fraction of A in liquid phase, xA = 0.3

Mole fraction of B in liquid phase, xB = 0.7

Now; PA=PA0xA

PB=PB0xB

= 100 * 0.7 = 70 torr

Mole fraction of B in vapour phase,  yB=PBPA+PB=7085

7085=x17

X = 14

New answer posted

a year ago

0 Follower 4 Views

P
Payal Gupta

Contributor-Level 10

For expansion in vacuum, workdone, w = 0

For isothermal process,  ΔU=0

According to first law of thermodynamics,

ΔU=q+wq=0

Get authentic answers from experts, students and alumni that you won't find anywhere else

Sign Up on Shiksha

On Shiksha, get access to

  • 67k Colleges
  • 1.2k Exams
  • 717k Reviews
  • 1850k Answers

Share Your College Life Experience

×
×

This website uses Cookies and related technologies for the site to function correctly and securely, improve & personalise your browsing experience, analyse traffic, and support our marketing efforts and serve the Core Purpose. By continuing to browse the site, you agree to Privacy Policy and Cookie Policy.