Chemistry

In H₂O (polar solvent) dibromophenol derivative and in CS₂ (non-polar solvent moneobromo phenol derivate is obtained.

^{$$ $Z=\frac{P{V}_m}{RT}\Rightarrow 0.5=\frac{24*V_m}{24}$}

^{$V_m=0.5\mathcal{l}/mole$}

^{$\left(P+\frac{a}{V_m^2}\right)\left(V_m-b\right)=RT$}

^{$\left(24+\frac{a}{0.5^2}\right)\left(0.5-0.1\right)=24$}

^{$24+\frac{a}{0.5^2}=60$}

^{$\frac{a}{0.5^2}=36$}

^{$a=36*0.5^2=9\frac{atm-{\mathcal{l}}^2}{mo{l}^2}$}
 

The blue color of the solution is due to the ammoniated electron which absorbs energy in infrared region of light

Therefore option (b) is correct.

$i=\frac{m_{theor}}{m_{app}}=\frac{30}{m_{app}}$

$\Delta T_b=i{k}_b.m]\underset{m-x}{\overset{m}{HA}}=\underset{x}{\overset{-}{H^{+}}}+\underset{x}{\overset{-}{A^{-}}}$

$0.0156=\left(\frac{m*x}{m}\right)*0.52*m$

m + x = 0.03

$\Rightarrow x=0.01\to i=1.5=\frac{30}{m_{app}}\Rightarrow m_{appp}=20$

Kindly go through the answer

30

Addition on triple bond takes place by the addition of hydrogen

(0) Path A to D is adiabatic.                                                                                                                                              

Kindly go through the answer

(6)

The Pauli exclusion principle states that no two electrons in an atom can have the same four quantum numbers. In other words, only two electrons may exist in the same atomic orbital, and these electrons must have opposite spins. (a) and (f) violate the Pauli exclusion principle. Hund's rule states that the most stable arrangement of electrons in subshells is the one with the greatest number of parallel spins. (b), (d) and (e) violate Hund's rule.