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6 months ago

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A
alok kumar singh

Contributor-Level 10

The partial pressure of dry N? is 758 - 14 = 744 mm Hg. Using the ideal gas law (PV=nRT), the moles of N? are calculated to be 1.25 * 10? ³ mol. This corresponds to 0.035 g of N? The percentage of nitrogen in the sample is (0.035 g / 0.1840 g) * 100, which is 18.96%.
Answer: 19 (Rounded)

New answer posted

6 months ago

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A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

6 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

6 months ago

0 Follower 6 Views

A
alok kumar singh

Contributor-Level 10

This problem involves the stoichiometry of acid-base neutralization.

o   For the reaction with H? PO? (a dibasic acid), 100 mL of NaOH is required.

o   For the reaction with H? PO? (a monobasic acid), 200 mL of NaOH is required.

New answer posted

6 months ago

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A
alok kumar singh

Contributor-Level 10

The Lassaign's test is a qualitative analysis method used to detect nitrogen, sulfur, phosphorus, and halogens in an organic compound. Copper (II) oxide is used to detect carbon. In the sodium fusion extract, halides (X? ) precipitate with AgNO? , and sulfide (S²? ) precipitates as black PbS.

New answer posted

6 months ago

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A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

6 months ago

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R
Raj Pandey

Contributor-Level 9

ΔG° = + 25.2 kJ / mol
Using ΔG° = -2.3 RT log Kp
25.2 * 10³ = - 2.3 * 8.3 * 400 log Kp

o   3.3 = log Kp
log (1 / 2*10³) = log Kp
Kp = 1 / (2*10³)
Using; Kp = Kc (RT)
1 / (2*10³) = Kc (0.083 * 400)? ¹

New answer posted

6 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

6 months ago

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R
Raj Pandey

Contributor-Level 9

V (Na? CO? ) = 10 mL
Volume of HCl used will be 5 mL (average of titre values)
Meq of HCl = meq of Na? CO?
(M * n-factor * V)HCl = (M * n-factor * V)Na? CO?
0.2 * 1 * 5 = M * 2*10
M= 0.05 M
M= 50 mM

New answer posted

6 months ago

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R
Raj Pandey

Contributor-Level 9

ClF? and XeF? have two lone pairs of electrons on central atom.

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