Class 11th

Get insights from 8k questions on Class 11th, answered by students, alumni, and experts. You may also ask and answer any question you like about Class 11th

Follow Ask Question
8k

Questions

0

Discussions

38

Active Users

0

Followers

New answer posted

2 months ago

0 Follower 5 Views

R
Raj Pandey

Contributor-Level 9

ΔG° = + 25.2 kJ / mol
Using ΔG° = -2.3 RT log Kp
25.2 * 10³ = - 2.3 * 8.3 * 400 log Kp

o   3.3 = log Kp
log (1 / 2*10³) = log Kp
Kp = 1 / (2*10³)
Using; Kp = Kc (RT)
1 / (2*10³) = Kc (0.083 * 400)? ¹

New answer posted

2 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

2 months ago

0 Follower 2 Views

R
Raj Pandey

Contributor-Level 9

V (Na? CO? ) = 10 mL
Volume of HCl used will be 5 mL (average of titre values)
Meq of HCl = meq of Na? CO?
(M * n-factor * V)HCl = (M * n-factor * V)Na? CO?
0.2 * 1 * 5 = M * 2*10
M= 0.05 M
M= 50 mM

New answer posted

2 months ago

0 Follower 2 Views

R
Raj Pandey

Contributor-Level 9

ClF? and XeF? have two lone pairs of electrons on central atom.

New answer posted

2 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

2 months ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

The difference between the first and second ionization energies is significantly higher for alkali metals (like Sodium, Na) compared to alkaline earth metals (like Magnesium, Mg). Therefore, in the context of the problem, X=Na and Y=Mg.

New answer posted

2 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

Iron (III) iodide (FeI? ) does not exist because it is unstable. The Fe³? ion is a strong enough oxidizing agent to be easily reduced to Fe²? by the I? ion, which in turn is oxidized.

New answer posted

2 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

Oxygen gas (O? ) is not considered a greenhouse gas.

New answer posted

2 months ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

In sodium hydride (NaH), hydrogen has an oxidation state of -1. In this state, it can only act as a reducing agent.

New answer posted

2 months ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

The atomic numbers and classifications for the given elements are: As (Arsenic, atomic no. 33) is a metalloid, I (Iodine, atomic no. 53) is a non-metal, and Bi (Bismuth, atomic no. 83) is a metal.

Get authentic answers from experts, students and alumni that you won't find anywhere else

Sign Up on Shiksha

On Shiksha, get access to

  • 65k Colleges
  • 1.2k Exams
  • 679k Reviews
  • 1800k Answers

Share Your College Life Experience

×
×

This website uses Cookies and related technologies for the site to function correctly and securely, improve & personalise your browsing experience, analyse traffic, and support our marketing efforts and serve the Core Purpose. By continuing to browse the site, you agree to Privacy Policy and Cookie Policy.