Class 11th
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New answer posted
6 months agoContributor-Level 9
Matching Processes with Catalysts:
o (a) Deacon's process: CuCl? used as catalyst
o (b) Contact process: V? O? used as catalyst
o (c) Cracking of hydrocarbon: ZSM-5 used as catalyst
o (d) Hydrogenation of vegetable oil: Particles Ni used as catalyst
New answer posted
6 months agoContributor-Level 9
Matching Compounds to their Class:
o Antacid: Cimetidine
o Artificial Sweetener: Alitame
o Antifertility: Novestrol
o Tranquilizers: Valium
New answer posted
7 months agoContributor-Level 10
Eutrophication is the process in which a water body becomes overly enriched with nutrients, leading to the plentiful growth of simple plant life.
New answer posted
7 months agoContributor-Level 9
While the particle moves from mean position to displacement, half of its amplitude, its phase changes by π/6 rad. So,
Time taken, t = (π/6)/ω = T/12 = (2/12)s = (1/6)s
a = 6
New answer posted
7 months agoContributor-Level 9
Using Conservation of Mechanical Energy at point-A and at point-B, we can write
K_B = U_A - U_B [Since K_A = 0]
⇒ (1/2)mv_B² = mg (h_A - h_B)
⇒ v_B = √ (2 * 10 * (10 - 5) = 10m/s
New answer posted
7 months agoContributor-Level 9
For Wire-A
F / (πr_A²) = Y (l_A / 2) . (1)
For Wire-B
F / (πr_B²) = Y (l_B / 4) . (2)
From equations (1) and (2), we can write
(l_A / (2r_A²) = (l_B / (4r_B²) ⇒ l_B/l_A = 2 (r_B/r_A)² ⇒ x = l_B = 32
New answer posted
7 months agoContributor-Level 9
Angle from direction of flow = 90° + θ = 120°
⇒ θ = 30°
sin 30° = u/v ⇒ u/10 = 1/2 ⇒ u = 5 m/s
New answer posted
7 months agoContributor-Level 10
The reaction is: FeCl? + 3H? C? O? + 3KOH → K? [Fe (C? O? )? ] (A) + 3HCl + 3H? O
In the complex [Fe (C? O? )? ]³? , the oxalate ion (C? O? )²? is a bidentate ligand.
There are three bidentate ligands, so the coordination number, or secondary valency, of Fe is 3 * 2 = 6.
New answer posted
7 months agoContributor-Level 10
The cell constant (G) is given by G = κ * R, where κ is conductivity and R is resistance.
Since the cell constant is constant: (κ * R)KCl = (κ * R)HCl
0.14 Sm? ¹ * 4.19 Ω = κ_HCl * 1.03 Ω
κ_HCl = (0.14 * 4.19) / 1.03 = 0.569 Sm? ¹
This is equivalent to 56.9 * 10? ² Sm? ¹.
The answer, rounded off, is 57.
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