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Class 11th

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10 months ago

Class 11th Chemistry Classification of Elements and Periodicity in Properties

Consider the elements Mg, Al, S, P and Si, the correct increasing order of their first ionization enthalpy is:

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alok kumar singh

Contributor-Level 10

Al < Mg < Si < S < P

1^st I. E increase along period with exception on moving from group 2 to group 13 and group 15 to group 16

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10 months ago

Class 11th Physics

In the reported figure of earth, the value of acceleration due to gravity is same at point A and C but it is smaller than that of its value at point B (surface of the earth). The value of OA: AB will be x : y. The value of x is…………

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Vishal Baghel

Contributor-Level 10

$\frac{G M}{{(3 R / 2)}^{2}} = \frac{G M}{R^{3}} * r$

$\Rightarrow O A = \frac{4 R}{9} = r$

$A B = R - \frac{4 R}{9} = \frac{5 R}{9} \Rightarrow O A : A B = 4 : 5 = x : y \Rightarrow x = 4$

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10 months ago

Class 11th Oscillation

A particle executes S.H.M. with amplitude 'a' and time period 'T'. The displacement of the particle when its speed is half of maximum speed is $\frac{\sqrt[]{x} a}{2} .$ The value of x is…………

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Vishal Baghel

Contributor-Level 10

$v = ω \sqrt[]{A^{2} - s^{2}} \Rightarrow \frac{A ω}{2} = ω \sqrt[]{A^{2} - s^{2}} \Rightarrow s = \frac{\sqrt[]{3} A}{2} \Rightarrow x = 3$

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10 months ago

Class 11th Maths

In the circle given below, let OA = 1 unit, OB = 13 unit and PQ $⊥$ OB. Then, the area of the triangle PQB (in square units) is

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Payal Gupta

Contributor-Level 10

By properties,

OA.AB = PA.AQ, OA=1, AB = 12

12 = a²

$a = 2 \sqrt[]{3}$

$∴ A r e a o f P Q B = \frac{1}{2} * 12 * 2.2 \sqrt[]{3} = 24 \sqrt[]{3}$ sq. units

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10 months ago

Class 11th Thermodynamics

1 mole of rigid diatomic gas performs a work of $\frac{Q}{5}$ when heat Q is supplied to it. The molar heat capacity of the gas during this transformation is $\frac{x R}{8} .$ The value of x is………

[R = universal gas constant]

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Vishal Baghel

Contributor-Level 10

$Δ Q = Δ U + Δ W$

^{$\Rightarrow Q = Δ U + \frac{Q}{5} \Rightarrow Δ U = \frac{4 Q}{5} = n C_{v} Δ T \Rightarrow \frac{4 Q}{5} = \frac{5 R}{2} Δ T \Rightarrow Δ T = \frac{8 Q}{25 R}$}

^{$Q = n c Δ T = 1 * C * \frac{80}{25 R} \Rightarrow C = \frac{25 R}{8} \Rightarrow x = 25$}

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10 months ago

Class 11th Thermodynamics

The volume V of a given mass of monoatomic gas changes with temperature T according to the relation $V = k T^{\frac{2}{3}} .$ The work done when temperature changes by 90 K will be xR. The value of x is…….

[R = universal gas constant]

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Vishal Baghel

Contributor-Level 10

$V = k T^{\frac{2}{3}}$

$T V^{- \frac{3}{2}} = K$

$\Rightarrow γ - 1 = - 3 / 2$

$\Rightarrow γ = - 1 / 2$

Work done = $\frac{n R Δ T}{- y + 1} = \frac{1 * R * 90}{3 / 2} = 6 R$

n = 60

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10 months ago

Class 11th Maths

The value of $-^{15} C_{1} + 2 .^{15} C_{2} - 3 .^{15} C_{3} + . . . . - 15 .^{15} C_{15} +^{14} C_{1} +^{14} C_{3} +^{14} C_{5} + . . . . +^{14} C_{11} i s :$

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alok kumar singh

Contributor-Level 10

= A + B (say)

(1 + x)¹⁵ =

differentiating 15 (1 + x)¹⁴ = $\sum r .^{15} C_{r} x^{r - 1}$

put = x = -1

$\Rightarrow 0 = -^{15} C_{1} + 2 .^{15} C_{2} - . . . . . . . = A$

$B =^{14} C_{13} = 2^{13}$

$∴ A + B = 2^{13} - 14$

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10 months ago

Class 11th Physics

Time period of a simple pendulum is T. The time taken to complete $\frac{5}{8}$ oscillations starting from mean position is $\frac{α}{β} T .$ The value of a is……….

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Vishal Baghel

Contributor-Level 10

Total oscillation = $\frac{1}{2} + \frac{1}{8} = \frac{5}{8}$ $\frac{}{} \frac{}{} \frac{}{}$

$\Rightarrow t i m e t a k e n = \frac{T}{2} + \frac{T}{12} = \frac{7 T}{12}$

= 7

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10 months ago

Class 11th Maths

The equation of the plane passing through the point (1, 2, -3) and perpendicular to the planes 3x + y – 2z = 5 and

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alok kumar singh

Contributor-Level 10

Let direction ratio of the normal to the required plane are l, m, n

$\begin{array}{l} ∴ 3 l + m - 2 n = 0 \\ ∴ 2 l - 5 m - n = 0 \\ ∴ \frac{l}{- 11} = \frac{m}{- 1} = \frac{n}{- 17} \end{array}$

Equation of required plane

11 (x – 1) + 1 (y – 2) + 17 (z + 3) = 0

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10 months ago

Class 11th Physics

Given below are two statements:

Statement I : A second's pendulum has a time period of 1 second.

Statement II : It takes precisely one second to move between the two extreme positions.

In the light of the above statements, choose the correct answer from the options given below:

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Vishal Baghel

Contributor-Level 10

Time period of second pendulum is 2 seconds. &nbs

...more

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