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11 months ago

Class 12th Chemistry NCERT Exemplar Solutions Class 12th Chapter Twelve

The major product in given the reaction is

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Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

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11 months ago

Class 12th Hydrogen

Which of the following forms of hydrogen emits low energy β - particles?

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Payal Gupta

Contributor-Level 10

Tritium is radioactive and it decays into He³ during emission of β-radiation

₁T³ → ₂He³ + _-1e⁰

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11 months ago

Class 12th Physics Oscillations

As per given figures, two spring constants k and 2k are connected to mass m. If period of oscillation in figure (a) is 3s, then the period of oscillation in figure (b) will be $\sqrt[]{x} s .$ The value of x is________.

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alok kumar singh

Contributor-Level 10

In figure a

$K_{e q} = \frac{k * 2 k}{3 k} = \frac{2 k}{3}$

$T = 2 Π \sqrt[]{\frac{3 M}{2 K}} = 3 s$

$\frac{I n f i g u r e b}{K_{e q} = 3 K}$

$T' = 2 Π \sqrt[]{\frac{M}{3 K}}$

$T' = \sqrt[]{2} \Rightarrow X = 2$

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11 months ago

Class 12th Physics NCERT Exemplar Solutions Class 12th Chapter Three

A potentiometer wire of length 300 cm is connected in series with a resistance 780 $Ω$ and a standard cell of emf 4V. A constant current flows through potentiometer wire. The length of the null point for cell of emf 20 mV is found to be 60 cm. The resistance of the potentiometer wire is ________ $Ω$ .

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alok kumar singh

Contributor-Level 10

$I = \frac{4}{R + 780}$

Potential Difference across AB = l * R = $\frac{4 R}{R + 780}$

Potential Difference across AC = $(\frac{4 R}{R + 780}) * \frac{60}{300}$

$\Rightarrow \frac{4 R}{5 (R + 780)} = 2 * 1 0^{- 2} \Rightarrow R = 20 Ω$

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11 months ago

Class 12th Organic Chemistry - Some Basic Principles and Tech

Identify A in the given reaction.

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Payal Gupta

Contributor-Level 10

Since SOCl₂ is used to covert aliphatic (R-OH) into chlorides. It will not react with aromatic alcohol

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11 months ago

Class 12th Physics NCERT Exemplar Solutions Class 12th Chapter Six

In a coil of resistance $8 Ω,$ the magnetic flux due to an external magnetic field varies with time as $ϕ = \frac{2}{3} (9 - t^{2}) .$ The value of total heat produced in the coil, till the flux becomes zero, will be_______J.

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alok kumar singh

Contributor-Level 10

$? = \frac{2}{3} (9 - t^{2}) = 0$

t = 3 sec

$E m f = \frac{- d ?}{d t} = \frac{4 t}{3}$

$l = \frac{E m f}{R} = \frac{\frac{4}{3} t}{8} = \frac{t}{6}$

Heat = $\int l^{2} R d t = \int_{0}^{3} \frac{t^{2}}{36} * 8 d t = 2 J$

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11 months ago

Class 12th physics ncert exemplar solution class 12th chapter one

Three point charges of magnitude $5 μ C, 0.16 μ C, a n d 0.3 μ C$ are located at the vertices A, B, C of a right angled triangle whose sides are AB = 3cm, BC = $3 \sqrt[]{2}$ and CA = 3 and point A is the right angle corner. Charge at point A experiences __________ N of electrostatic force due to the other two charges.

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alok kumar singh

Contributor-Level 10

$F_{1} = \frac{9 * 1 0^{9} * 5 * 1 0^{- 6} * 0.3 * 1 0^{- 6}}{9 * 1 0^{- 4}}$

= 15 N

$F_{2} = \frac{9 * 1 0^{9} * 5 * 1 0^{- 6} * 0.16 * 1 0^{- 6}}{9 * 1 0^{- 4}}$

= 8N

$\Rightarrow F_{n e t} = \sqrt[]{{(15)}^{2} + {(8)}^{2}}$

= 17 N

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11 months ago

Class 12th Physics NCERT Exemplar Solutions Class 12th Chapter Fourteen

The typical transfer characteristics of a transistor in CE configuration is shown in figure. A load resistor of $2 k Ω$ is connected in the collector branch of the circuit used. The input resistance of the transistor is $0.50 k Ω .$ The voltage gain of the transistor is________.

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alok kumar singh

Contributor-Level 10

Voltage gain = $\frac{Δ l_{C}}{Δ l_{B}} * \frac{R_{C}}{R_{B}}$

$\frac{5 * 1 0^{- 3}}{100 * 1 0^{- 6}} * \frac{2}{0.5}$

= 200

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11 months ago

Class 12th Physics NCERT Exemplar Solutions Class 12th Chapter Fourteen

In the circuit shown below, maximum zener diode current will be _________mA.

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Vishal Baghel

Contributor-Level 10

$l = \frac{120 - 60}{4000} = 0.015 A$

Thus l₂ = l - L_L

= 0.015 – 0.006

= 0.009 = 9mA

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11 months ago

Class 12th Physics NCERT Exemplar Solutions Class 12th Chapter Nine

A uniformly heavy rod of mass 20kg, cross sectional area 0.4 m² an length 20m is hanging from a fixe support. Neglecting the lateral contraction. The elongation in the rod due to its own weight is x * 10^-9m. The value of x i________.

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alok kumar singh

Contributor-Level 10

$\int_{0}^{Δ l} d y = \int_{0}^{l} (\frac{m g}{l}) * \frac{d x}{A Y}$

$\Rightarrow Δ l = \frac{m g l}{2 A Y} = 25 * 1 0^{- 9} m$

$\Rightarrow x = 25.00$

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