Class 12th

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New answer posted

a year ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

New answer posted

a year ago

0 Follower 1 View

P
Payal Gupta

Contributor-Level 10

Time period of second pendulum is 2 seconds.

New answer posted

a year ago

0 Follower 4 Views

V
Vishal Baghel

Contributor-Level 10

 P1=cos? =Rz=RXL2+R2

P1=cos? =RR2=12

So,  P1P2=12

New answer posted

a year ago

0 Follower 4 Views

V
Vishal Baghel

Contributor-Level 10

 Speed  of  light  C=wk=1.5*10110.5*103=3*108m/s

So, E0 = B0 C

= 2 * 10-8 * 3 * 108

= 6v/m

Direction will be along z – axis

New answer posted

a year ago

0 Follower 5 Views

P
Payal Gupta

Contributor-Level 10

Consider the following image dddddddddddddddddddddddddddddddddddddd

New answer posted

a year ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

KE=ρ22m

⇒ρ2αm

⇒ (P1P2)2=82=41

⇒P1P2=21

New answer posted

a year ago

0 Follower 4 Views

V
Vishal Baghel

Contributor-Level 10

 β=12mm=12*10−3m

β'=βμ=12*10−34/3=9*10−3mβ'=9mm

New question posted

a year ago

0 Follower 3 Views

New answer posted

a year ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

 E=I  A

=100*1*10−4

=10−2W

E=nhcλ

10−2=n?   *6.64*10−34*3*108900*10−9

n? =10−2*9*10−76.64*10−34*3*108

n? =4.5*1016

New answer posted

a year ago

0 Follower 4 Views

P
Payal Gupta

Contributor-Level 10

Bv = B sin 60°

Bv=2.5*10−4*32

Emf=Bv*v*l=2.5*10−4*32*180*518*1=108.25*10−3volts

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