Class 12th

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New answer posted

6 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

New answer posted

6 months ago

0 Follower 1 View

P
Payal Gupta

Contributor-Level 10

Time period of second pendulum is 2 seconds.

New answer posted

6 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

 P1=cos? =Rz=RXL2+R2

P1=cos? =RR2=12

So,  P1P2=12

New answer posted

6 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

 SpeedoflightC=wk=1.5*10110.5*103=3*108m/s

So, E0 = B0 C

= 2 * 10-8 * 3 * 108

= 6v/m

Direction will be along z – axis

New answer posted

6 months ago

0 Follower 3 Views

P
Payal Gupta

Contributor-Level 10

Consider the following image dddddddddddddddddddddddddddddddddddddd

New answer posted

6 months ago

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A
alok kumar singh

Contributor-Level 10

KE=ρ22m

ρ2αm

(P1P2)2=82=41

P1P2=21

New answer posted

6 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

 β=12mm=12*103m

β'=βμ=12*1034/3=9*103mβ'=9mm

New question posted

6 months ago

0 Follower 3 Views

New answer posted

6 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

 E=IA

=100*1*104

=102W

E=nhcλ

102=n? *6.64*1034*3*108900*109

n? =102*9*1076.64*1034*3*108

n? =4.5*1016

New answer posted

6 months ago

0 Follower 3 Views

P
Payal Gupta

Contributor-Level 10

Bv = B sin 60°

Bv=2.5*104*32

Emf=Bv*v*l=2.5*104*32*180*518*1=108.25*103volts

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