Class 12th

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New answer posted

11 months ago

0 Follower 12 Views

A
alok kumar singh

Contributor-Level 10

Uinitial =k (4q) (q) (d/2)+k (q) (-q) (d/2)

6kq2dUfinal =4 (4q) (q)3d2+k (q) (-q) (d/2)23kq2dΔU=23-6kq2d-163kq2d

New answer posted

11 months ago

0 Follower 9 Views

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution 

New answer posted

11 months ago

0 Follower 15 Views

A
alok kumar singh

Contributor-Level 10

V 2 = U 2 + 2 g S V 2 = 0 + 2 g ( h - y ) V 2 = 2 g h - 2 g y V = 2 g h - 2 g y

New answer posted

11 months ago

0 Follower 2 Views

R
Rashmi Kumar

Contributor-Level 10

Candidates seeking admission to the certificate programme can enrol for admission with Class 12 marks. Candidates must complete Class 12 to enrol for the certificate course. The college offers only two certificate courses, i.e.,  Digital Marketing Course and Interior Designing. Paperloft Institute admissions are merit-based. 

New answer posted

11 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

 l=600π2 (sin6xsin4xsinx+sin4xsin2xsinx+sin2xsinx)dx

l=600π2 (2cos5x+2cos3x+2cosx)dx

l=60 (25sin5x+23sin3x+2sinx)|0π/2 = 104

New answer posted

11 months ago

0 Follower 5 Views

V
Vishal Baghel

Contributor-Level 10

X  0 1 2 3

P (X) 16 12 310 130

σ2=Σx2P (x) (Σ*P (x)2=56100)

100σ2=56

New answer posted

11 months ago

0 Follower 57 Views

V
Vishal Baghel

Contributor-Level 10

 |z2|=|z¯|.21|z||z|=1

z2=z¯z3=1

z=worw2

wn= (1+w)n= (w2)n

New answer posted

11 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

 tan? +5tan2? tan? =5? tan2?

tan3? =5

? =n? 3+? 3tan? =5

Five solution.

New answer posted

11 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

 6312+10 (1311+2310+2239+2338+....+2103)

6312=10311 (611161)

=212.1m.n=12

New answer posted

11 months ago

0 Follower 7 Views

V
Vishal Baghel

Contributor-Level 10

 y2=x2

y=mx18m

This tangent pass through (2, 0)

m=±14i.e., onetangentisx4y2=0, 17r=9

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