Class 12th

As, Ed = VB

$\therefore E=\frac{V_B}{d}=\frac{0.6}{6*10^{-6}}=1*10^{5}N/C$

Kindly go through the solution 

Sol.

This is a True or False Type Questions as classified in NCERT Exemplar

$\begin{array}{l}False.\\ Since{\left(AB\right)}^{\text{'}}=B^{\text{'}}{A}^{\text{'}}.\end{array}$

For angle of incidence 'i' :-

cos I = $\frac{5}{\sqrt[]{48+27+25}}=\frac{5}{\sqrt[]{100}}$

i = 60°

Using snell's law :-

${\mu }_{1}sini={\mu }_{2}sinr$

sin r = $\frac{\sqrt[]{2}}{\sqrt[]{3}}sin60°=\sqrt[]{\frac{2}{3}}*\frac{\sqrt[]{3}}{2}=\frac{1}{\sqrt[]{2}}$

$\therefore r=45°$

So, difference, I – r = 60° - 452 = 15°

This is a True or False Type Questions as classified in NCERT Exemplar

$\begin{array}{l}True.\\ LetA,B,andCbethreematricesofthesameorder.\\ Giventhat{A}^{\text{'}}=A,B^{\text{'}}=B,and{C}^{\text{'}}=C\\ LetP=A+B+C\\ \Rightarrow P^{\text{'}}={\left(A+B+C\right)}^{\text{'}}\\ =A^{\text{'}}+B^{\text{'}}+C^{\text{'}}=A+B+C=P\\ So,A+B+Cisalsoasymmetricmatrix.\end{array}$

This is a True or False Type Questions as classified in NCERT Exemplar

$\begin{array}{l}False.\\ FortwosquarematricesAandB,AB=BAisnotalwaystrue.\end{array}$

$\mathcal{l}=2\pi r$

$\Rightarrow 314cm=2*3.14r$

$\Rightarrow r=\raisebox{1ex}{$1$}\!\left/ \!\raisebox{-1ex}{$2$}\right.m=0.5m$

$\mu =iA$

$=14*\pi r^2$

$=14^2*\frac{22}{7}*\frac{1}{4}=11$

This is a True or False Type Questions as classified in NCERT Exemplar

Sol.

Kindly go through the solution 

This is a True or False Type Questions as classified in NCERT Exemplar

$\begin{array}{l}False.\\ Sinceforanytwonon-zeromatricesAandB,wemaygetAB=0.\end{array}$