Class 12th

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New answer posted

6 months ago

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P
Payal Gupta

Contributor-Level 10

This is a Fill in the blanks Type Questions as classified in NCERT Exemplar

L e t A b e a m a t r i x A = 1 . A H e n c e , n e g a t i v e o f a m a t r i x i s o b t a i n e d b y m u l t i p l y i n g i t b y 1 .

New answer posted

6 months ago

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P
Payal Gupta

Contributor-Level 10

This is a Fill in the blanks Type Questions as classified in NCERT Exemplar

L e t A a n d B b e a n y t w o m a t r i c e s F o r s k e w s y m m e t r i c m a t r i c e s A = A ' ( i ) a n d B = B ' ( i i ) A d d i n g ( i ) a n d ( i i ) w e g e t A + B = A ' B ' A + B = ( A ' + B ' ) , s o A + B i s s k e w s y m m e t r i c m a t r i x . H e n c e , t h e s u m o f t w o s k e w s y m m e t r i c m a t r i c e s i s a l w a y s s k e w s y m m e t r i c m a t r i c e s .

New answer posted

6 months ago

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A
alok kumar singh

Contributor-Level 10

Sol.
           
 

 

New answer posted

6 months ago

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A
alok kumar singh

Contributor-Level 10

Sol. 2 P b N O 3 2 ? Δ 2 P b O + 2 N O 2 + O 2

2 N O 2 ? N 2 O 4 colourless

N 2 O 4 + 2 N O ? 2 N 2 O 3

Oxidation state in N 2 O 3  is +3

New answer posted

6 months ago

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Payal Gupta

Contributor-Level 10

This is a Fill in the blanks Type Questions as classified in NCERT Exemplar

N u l l m a t r i x i . e . [ 0 0 0 0 ] o r [ 0 0 0 0 0 0 0 0 0 ] i s b o t h s y m m e t r i c a n d s k e w s y m m e t r i c m a t r i x .

New answer posted

6 months ago

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A
alok kumar singh

Contributor-Level 10

Sol. C r 2 + and F e 2 +  both have 4 unpaired electrons.

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6 months ago

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P
Payal Gupta

Contributor-Level 10

This is an Objective Type Questions as classified in NCERT Exemplar

W e h a v e , [ 4 2 3 3 ] = [ 1 2 0 3 ] [ 2 0 1 1 ] UsingelementaryrowtransformationR1R13R2,weget [ 5 7 3 3 ] = [ 1 7 0 3 ] [ 2 0 1 1 ] H e n c e , t h e c o r r e c t o p t i o n i s ( a ) .

New answer posted

6 months ago

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Payal Gupta

Contributor-Level 10

This is an Objective Type Questions as classified in NCERT Exemplar

G i v e n t h a t : [ 1 3 2 4 ] = [ 1 1 0 1 ] [ 3 1 2 4 ] UsingC2C22C1,weget [ 1 5 2 0 ] = [ 1 1 0 1 ] [ 3 5 2 0 ] H e n c e , t h e c o r r e c t o p t i o n i s ( d ) .

New answer posted

6 months ago

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A
alok kumar singh

Contributor-Level 10

Sol. Balmer series lies in the visible region.

New answer posted

6 months ago

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P
Payal Gupta

Contributor-Level 10

This is an Objective Type Questions as classified in NCERT Exemplar

W e k n o w t h a t f o r a n y t w o m t r i c e s A a n d B , w e m a y h a v e A B = B A , A B B A a n d A B = 0 , b u t i t i s n o t a l w a y s t r u e . H e n c e , t h e c o r r e c t o p t i o n i s ( d ) .

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