JEE Main
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New answer posted
3 years ago
0 Follower
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Group Captain Vinayak DeodharLa vie est faite pour vivre pas pour stresser
Scholar-Level 18
Hello Harivel, the basic eligibility to get admission in Amrutha is their own entrance exam and hence your performance in JEE Mains will not have much effect on your eligibility to get admission. However if you have scored 78.5 percentile in JEE Mains then I am sure you will do well in the entrance exam conducted by Amrutha and then you can get admission their. The last date is just around the corner on 18th of April. I am attaching a link that will give you all the required information about this entrance examination. https://www.shiksha.com/college/amrita-school-of-engineering-amrita-vishwa-vidyapeetham-Coimbatore-36898/admission
Best
Best
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New answer posted
3 years ago
0 Follower
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Group Captain Vinayak DeodharLa vie est faite pour vivre pas pour stresser
Scholar-Level 18
Hello Rashmi Rekha Tarai, the second and the last session of JEE Mains examination conducted by National testing agency has concluded on 15th of April. I am sure that you would have attempted this examination with or without mock test. For the purpose of record I can say that plenty of agencies offer to conduct mock test for JEE Mains and many students do take these test. It definitely makes them aware as to where they stand with respect to their preparation. I am sure that you also would have taken mock test offered by one or the other institution and also that it would have helped you in actual examination. Best wishes to you.
New answer posted
3 years ago
0 Follower
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Group Captain Vinayak DeodharLa vie est faite pour vivre pas pour stresser
Scholar-Level 18
Firstly admissions to National Institute of Technology are given based on the performance in examination called JEE Mains. As a matter of fact there is no other examination which is required to be cleared by the student to get admission in these institutes. On the other hand JEE Advanced examination will lead students for admission in IIT's. Thus we can SEE that these two examinations are required for taking admission in two different Sets of Institutions. Also there is no other examination that can get a student admission in either of these to Sets of institutions. In view of foregoing, we can conclude that these are the only two exam
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New answer posted
3 years ago
0 Follower
8 Views
Group Captain Vinayak DeodharLa vie est faite pour vivre pas pour stresser
Scholar-Level 18
Hello Gutta Sai Vindhya, unfortunately your query has come upfront almost one year after you posted. By now perhaps, there is no relevance. You must have taken admission into your dream college and branch. Right? But to help other students similarly placed at this juncture, I am attaching a link that can predict the college and branch thst you can get based on results in this entrance test. https://www.shiksha.com/engineering/ap-eamcet-college-predictor
Best wishes to you.
Best wishes to you.
New answer posted
3 years ago
0 Follower
152 Views
R
Rishi Rathore
Beginner-Level 5
According to analysis of all shifts paper and comparison with marks vs percentile of first attempt, you can accept around 90-93 %ile in this attempt. Which means your rank can be between 70k-100k. The general cut-off will be around 85 marks for this shift. The difficulty Level of this shift was moderate.
New answer posted
3 years ago
0 Follower
9 Views
Sattwik Kumar MardanInterested in BCA
Contributor-Level 9
It is not possible to accurately predict the seat (branch+college) you will get in WBJEE counseling with just your JEE Main percentile. Your WBJEE rank is determined by your performance in the WBJEE exam, which has a different marking scheme and difficulty level than JEE Main. Additionally, the availability of seats in each college and branch can change each year based on various factors. It is recommended that you check the previous year's opening and closing ranks of colleges and branches you are interested in to get an idea of the expected rank range for admission. You can also use the WBJEE rank predictor tool to get an estimated r
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