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New answer posted
a year agoContributor-Level 10
f : R defined as
domain of fog (x) R – {-1, 1} and range
fog (x) is neither one-one nor onto
New answer posted
a year agoContributor-Level 10
GOF is differentiable at x = 0
So R.H.D = L.H.D.
⇒ 4 = 6 – k1 Þ k1 = 2
Now g (f (-4) + g (f (4)
= 2 (2e4 – 1)
New answer posted
a year agoNew question posted
a year agoNew question posted
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