Ncert Solutions Chemistry Class 11th

For the reaction A_(g) -> B_(g) the value of the equilibrium constant at 300K and 1 atm is equal to 100.0 The value of ${\Delta }_{r}G$ for the reaction at 300K and 1 atm in J mol^-1 is -xR, where x is_________.

(Rounded off to the nearest integer)

[R = 8.31 J mol^-1 K^-1 and In 10 = 2.3]

Number of amphoteric compounds among the following is___________.

(a) BeO     (B) BaO                          (c) Be(OH)₂                       (d) Sr(OH)₂

The gas released during anaerobic degradation of vegetation may lead to:

(A) HOCl + H₂O₂ -> H₃O⁺ + Cl^- + O₂

(B)  $I_2+H_2{O}_2+2O{H}^{-}\to 2I^{-}+2H_{2}O+O_2$  

Choose the correct option.

When 400 mL of 0.2 M H₂SO₄ solution is mixed with 600 mL of of 0.1 M NaOH solution the increase in temperature of the final solution is _____ *10⁻² K. (Round off to the Nearest Integer).
[Use : H⁺(aq) + OH⁻(aq) → H₂O : ΔₙH = –57.1kJmol⁻¹
Specific heat of H₂O = 4.18JK⁻¹g⁻¹
Density of H₂O = 1.0gcm⁻³
Assume no change in volume of solution on mixing]

The equilibrium constant for the reaction
A(s) ⇌ M(s) + ½ O₂(g)
ln Kp = 4. At equilibrium, the partial pressure of O₂ is _____ atm. (Round off to the Nearest Integer).

Certain fixed quantity of an ideal gas expands by adiabatic manner such that w_gas is equal to -25 kJ and ∆H_gas for the expansion is -75kJ. The ratio of C_p/C_v for this gas will be equal to:

Given that ∆c H° (combustion enthalpy) for Diamond is -834.8 kJ mole and ∆c H° for graphite is -832.8 kJ/mole, the value of ∆f H°(Diamond) i.e. [C(graphite) → C(diamond)] [in kJ/mole] is:

At critical condition of temperature and pressure for a real gas, what would be the value of 16 Z? Here, Z is its compressibility factor.

10.30 mg of O₂ is dissolved in 1L of sea water of density 1.03 g/mL. The concentration of O₂ in ppm is _______.