Ncert Solutions Chemistry Class 11th

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6 months ago

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A
alok kumar singh

Contributor-Level 10

In both reactions H2O2 act as reducing agent

In reaction (A)       HOCl – O.A

H2O2 – R.A

In reaction (B)       I2 – O.A

H2O2 – R.A

New answer posted

6 months ago

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A
alok kumar singh

Contributor-Level 10

H? SO? + 2NaOH → Na? SO? + 2H? O
Milli mole: 80 60 (limiting reagent)
H? + OH? → H? O
Milli mole: 160 60
Milli mole: 160-60 0 60
Total heat produced = (60/1000) x 57.1 x 1000 = 3426 J
Total heat absorbed = msΔT
ΔT = Totalheat / (m x s)
= 3426J / (1000 x 4.18) = 0.819K
= 81.9 x 10? ² K
Ans. = 82 (the nearest)

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6 months ago

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alok kumar singh

Contributor-Level 10

Kp = (Po? )¹/² = 4
Po? = 16 atm

New answer posted

6 months ago

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V
Vishal Baghel

Contributor-Level 10

ΔH / ΔU = C? / C? = 75 / 25 = 3

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6 months ago

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V
Vishal Baghel

Contributor-Level 10

C (graphite) → C (diamond)
ΔH? = Δ? H° (graphite) - Δ? H° (Diamond) = -832.8 - [-834.8] = 2kJ/mole

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6 months ago

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V
Vishal Baghel

Contributor-Level 10

16 [Z] = 16 [3/8] = 6

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6 months ago

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V
Vishal Baghel

Contributor-Level 10

ppm of O? = (wt. of O? ) / (wt. of H? O) * 10?
= (10.3 mg) / (1.03 * 10? mg) * 10?
= 10ppm

New answer posted

6 months ago

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A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

6 months ago

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A
alok kumar singh

Contributor-Level 10

(A) Carbon monoxide – Haemoglobin
(B) Sulphur dioxide – Stiffness of flower buds
(C) Polychlorinated biphenyls – Carcinogenic
(D) Oxides of nitrogen – Metabolized by pyrus plants

New answer posted

6 months ago

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Vishal Baghel

Contributor-Level 10

Due to I, ClO? > BrO? > IO? (stability)

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