Ncert Solutions Chemistry Class 11th

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A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

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A
alok kumar singh

Contributor-Level 10

(A) Carbon monoxide – Haemoglobin
(B) Sulphur dioxide – Stiffness of flower buds
(C) Polychlorinated biphenyls – Carcinogenic
(D) Oxides of nitrogen – Metabolized by pyrus plants

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V
Vishal Baghel

Contributor-Level 10

Due to I, ClO? > BrO? > IO? (stability)

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Vishal Baghel

Contributor-Level 10

C? H? + 5O? → 3CO? + 4H? O
ΔH = − {6 (C = O) + 8 (OH)} + 2 (C – C) + 8 (C – H) + 5 (O = O)
= 8a? + 5a? + 2a? - 6a? - 8a?

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R
Raj Pandey

Contributor-Level 9

Vapourisation of H 2 O , H 2 O ( l ) H 2 O ( g )  

Mole of H2O = 3 6 1 8 = 2 m o l  


Δ E = Δ H Δ n R T  

= 4 1 . 1 1 * 8 . 3 1 * 3 7 3 1 0 0 0 = 3 8 k J / m o l e  

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Vishal Baghel

Contributor-Level 10

ΔG = -TΔS_universe

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Vishal Baghel

Contributor-Level 10

Ease of liquefaction depends on a/b value.

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alok kumar singh

Contributor-Level 10

(a) Li → used in bearings for motor engine.
(b) Na → used as coolant in fast breader nuclear reactor.
(c) K → used as absorbent of CO?
(d) Cs → used in photoelectric call.

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Vishal Baghel

Contributor-Level 10

Meq of K? Cr? O? is greater than all the other given species.

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Vishal Baghel

Contributor-Level 10

Bromobenzene is formed in first step (Sandmeyer reaction), which further gives phenyl magnesium bromide. Phenyl magnesium bromide further gives benzene with water.

+Mg (Br)OH

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