Ncert Solutions Chemistry Class 11th
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At Boyle's Temperature ; gas behaves ideally for a range of pressure.
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Consider the assertion and reason given below:
Assertion (A) : Buta-1,3 - diene is a monomer of gutta percha.
Reason (R) : Gutta Percha is formed through cationic addition polymerisation Choose the correct answer from the following:
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Consider the assertion and reason given below:
Assertion (A) : Buta-1,3 - diene is a monomer of gutta percha.
Reason (R) : Gutta Percha is formed through cationic addition polymerisation Choose the correct answer from the following:
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Gutta percha is a synthetic rubber and its monomer is isoprene .
Since isoprene has EDG, so it is prepared by cationic addition polymerization
Upvote Among the nitrates of alkaline earth metals, the thermal stability of Mg(NO3)2 and Sr(NO3)2 respectively are:
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Among the nitrates of alkaline earth metals, the thermal stability of Mg(NO3)2 and Sr(NO3)2 respectively are:
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Thermal stability of compound is directly proportional to large anion of s-block elements:
T.S ∝ 1/ (PP of cation)
And p.p. ∝ charge ∝ 1/size, So, [T.S. ∝ size ∝ 1/ (charge)]
So, Sr [NO? ]? is highly stable
But Mg (NO? )? ⇒ poor
Upvote Molality of sulphuric acid solution in which the mole fraction of water is 0.74 is:
Molality of sulphuric acid solution in which the mole fraction of water is 0.74 is:
? Solvent is H? O, which is in excess
So using m ( molality ) = (x? ×1000)/ (x? × (M? )? )
? x? = 0.74 (Mol? = 18 g)
x? = 1 – 0.74 = 0.26 ∴ m = (0.26 × 1000)/ (0.74 × 18) = 19.5
Upvote For a photochemical reaction A → B, 1.0×10-5 mole of B were formed on absorbing 1.2 × 1019 photons, quantum efficiency is : (NA = 6 × 1023)
For a photochemical reaction A → B, 1.0×10-5 mole of B were formed on absorbing 1.2 × 1019 photons, quantum efficiency is : (NA = 6 × 1023)
Number of mol of A reacted = 1×10? = 10?
Number of molecule of A = 10? × 6 ×10²³
Quantum efficiency = (6 ×10¹? ) / (1.2 ×10¹? ) = 0.50
Upvote The equilibrium constant Kp for a homogenous gaseous reaction is 10-3, the standard Gibb's free energy change (ΔG°) in cal mol-1 for the reaction at 27°C (using R = 2 cal K-1 mol-1) is :
The equilibrium constant Kp for a homogenous gaseous reaction is 10-3, the standard Gibb's free energy change (ΔG°) in cal mol-1 for the reaction at 27°C (using R = 2 cal K-1 mol-1) is :
ΔG° = – 2.303RT log Kp = – 2.303× 2 × 300log10? ³
= – 2.303× 2 × 300 × (– 3) = 4145.4cal mol? ¹
Upvote Two glass bulbs A and B are connected by a very small tube having a stop-cock. Bulb A has a volume of 100 cm³ and contained the gas; while bulb B was empty. On opening the stop-cock, the pressure fell down to 40%. The volume (in mL) of the bulb B must be :
Two glass bulbs A and B are connected by a very small tube having a stop-cock. Bulb A has a volume of 100 cm³ and contained the gas; while bulb B was empty. On opening the stop-cock, the pressure fell down to 40%. The volume (in mL) of the bulb B must be :
P? = 1atm
P? = 1atm × 40/100 = 0.40atm
V? = 100 cm³
V? =?
At constant temperature, P? V? = P? V?
So V? = (P? V? ) / P? = (1atm × 100 cm³) / 0.40 atm = 250cm³
Hence, the volume of bulb B = (250 –100) cm³ = 150 cm³
Upvote A 500g tooth-paste sample has 0.2g fluoride concentration. What is the concentration of fluoride in terms of ppm level ?
A 500g tooth-paste sample has 0.2g fluoride concentration. What is the concentration of fluoride in terms of ppm level ?
As 500g of tooth-paste has = 0.2g of F?
So, 10 g of toothpaste has = (0.2g × 10? g) / 500g F = 400g of F
Hence, concentration in ppm is 400.
Upvote ΔH_f° of CO₂(g), CO(g), N₂O(g) and NO₂(g) in kJ mol⁻¹ respectively is -393, -110, 81 and 34. Calculate the ΔH in kJ for the following reaction :
2NO₂(g) + 3CO(g) → N₂O(g) + 3CO₂(g).
ΔH_f° of CO₂(g), CO(g), N₂O(g) and NO₂(g) in kJ mol⁻¹ respectively is -393, -110, 81 and 34. Calculate the ΔH in kJ for the following reaction :
2NO₂(g) + 3CO(g) → N₂O(g) + 3CO₂(g).
ΔH_rxn = ΔH_f (N? O, g) + 3ΔH_f (CO? , g) – (2ΔH_f NO? , g) – 3ΔH_f (CO, g)
= 81 + 3× (– 393) – 2 × 34 – 3 (–110)
= 81 – 1179 – 68 + 330 = – 836 kJ
Upvote One mole of water is converted to vapour at its boiling point which is 100°C and at 1 atm. For this process, which one of following statement is correct?
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One mole of water is converted to vapour at its boiling point which is 100°C and at 1 atm. For this process, which one of following statement is correct?
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One mole of water is converted to vapour at its boiling point which is 100°C and at 1 atm. For this process ΔG = 0. As phase transformation of water is an equilibrium process and at equilibrium, free energy change is always zero.
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