Ncert Solutions Chemistry Class 11th

At Boyle's Temperature ; gas behaves ideally for a range of pressure.

Gutta percha is a synthetic rubber and its monomer is isoprene .
Since isoprene has EDG, so it is prepared by cationic addition polymerization

Thermal stability of compound is directly proportional to large anion of s-block elements:

T.S ∝ 1/ (PP of cation)

And p.p. ∝ charge ∝ 1/size, So, [T.S. ∝ size ∝ 1/ (charge)]

So, Sr [NO? ]? is highly stable

But Mg (NO? )? ⇒ poor

? Solvent is H? O, which is in excess

So using m ( molality ) = (x? *1000)/ (x? * (M? )? )

? x? = 0.74 (Mol? = 18 g)

x? = 1 – 0.74 = 0.26 ∴ m = (0.26 * 1000)/ (0.74 * 18) = 19.5

Number of mol of A reacted = 1*10? = 10?
Number of molecule of A = 10? * 6 *10²³
Quantum efficiency = (6 *10¹? ) / (1.2 *10¹? ) = 0.50

ΔG° = – 2.303RT log Kp = – 2.303* 2 * 300log10? ³
= – 2.303* 2 * 300 * (– 3) = 4145.4cal mol? ¹

P? = 1atm
P? = 1atm * 40/100 = 0.40atm
V? = 100 cm³
V? =?
At constant temperature, P? V? = P? V?
So V? = (P? V? ) / P? = (1atm * 100 cm³) / 0.40 atm = 250cm³
Hence, the volume of bulb B = (250 –100) cm³ = 150 cm³

As 500g of tooth-paste has = 0.2g of F?
So, 10 g of toothpaste has = (0.2g * 10? g) / 500g F = 400g of F
Hence, concentration in ppm is 400.

ΔH_rxn = ΔH_f (N? O, g) + 3ΔH_f (CO? , g) – (2ΔH_f NO? , g) – 3ΔH_f (CO, g)
= 81 + 3* (– 393) – 2 * 34 – 3 (–110)
= 81 – 1179 – 68 + 330 = – 836 kJ

One mole of water is converted to vapour at its boiling point which is 100°C and at 1 atm. For this process ΔG = 0. As phase transformation of water is an equilibrium process and at equilibrium, free energy change is always zero.