Ncert Solutions Chemistry Class 11th

Factual on lyophilic colloids
(A) It is easy to prepare
(B) Stable
(C) Revisable
(D) Viscosity is high and surface tension is low for DP. and DM.

Sm ⇒ +2, +3 (4f? , 6 s²); Gd ⇒ +3 (4f?5 d¹6 s²)
Tm ⇒ +2 + 3 (4f¹³,6 s²); Nd ⇒ +2, +3, +4 (4f? , 6 s²)

  $Zn+2NaOH\to N{a}_{2}Zn{O}_2+H_2\uparrow$

$\begin{array}{l}2AI+2NaOH+H_{2}O\to 2NaAl{O}_2+3H_2\uparrow \\ Sn+2NaOH+H_{2}O\to NaSn{O}_3+2H_2\uparrow \\ P_4+3NaOH+3H_{2}O\to P{H}_3\uparrow +3Na{H}_{2}P{O}_2\end{array}$

At Boyle's Temperature ; gas behaves ideally for a range of pressure.

Gutta percha is a synthetic rubber and its monomer is isoprene .
Since isoprene has EDG, so it is prepared by cationic addition polymerization

Thermal stability of compound is directly proportional to large anion of s-block elements:

T.S ∝ 1/ (PP of cation)

And p.p. ∝ charge ∝ 1/size, So, [T.S. ∝ size ∝ 1/ (charge)]

So, Sr [NO? ]? is highly stable

But Mg (NO? )? ⇒ poor

? Solvent is H? O, which is in excess

So using m ( molality ) = (x? *1000)/ (x? * (M? )? )

? x? = 0.74 (Mol? = 18 g)

x? = 1 – 0.74 = 0.26 ∴ m = (0.26 * 1000)/ (0.74 * 18) = 19.5

Number of mol of A reacted = 1*10? = 10?
Number of molecule of A = 10? * 6 *10²³
Quantum efficiency = (6 *10¹? ) / (1.2 *10¹? ) = 0.50

ΔG° = – 2.303RT log Kp = – 2.303* 2 * 300log10? ³
= – 2.303* 2 * 300 * (– 3) = 4145.4cal mol? ¹

P? = 1atm
P? = 1atm * 40/100 = 0.40atm
V? = 100 cm³
V? =?
At constant temperature, P? V? = P? V?
So V? = (P? V? ) / P? = (1atm * 100 cm³) / 0.40 atm = 250cm³
Hence, the volume of bulb B = (250 –100) cm³ = 150 cm³