Ncert Solutions Chemistry Class 11th
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Gadolinium has a low value of third ionisation enthalpy because of:
Gadolinium has a low value of third ionisation enthalpy because of:
Gadolinium has outer configuration of [Xe]4f?5d¹6s².
Its third ionization energy is low due to highly exchange energy and hence stability of the half-filled f subshell.
Match List-I with List-II.
List -I(Hydrides)
(a) MgH₂
(b) GeH₄
(c) B₂H₆
(d) HF
List - II (Nature)
(i) Electron precise
(ii) Electron deficient
(iii) Electron rich
(iv) Ionic
Choose the correct answer from the options given below:
Match List-I with List-II.
List -I(Hydrides)
(a) MgH₂
(b) GeH₄
(c) B₂H₆
(d) HF
List - II (Nature)
(i) Electron precise
(ii) Electron deficient
(iii) Electron rich
(iv) Ionic
Choose the correct answer from the options given below:
MgH? is an ionic or saline hydride, GeH? is an electron precise hydride with 8 electrons around Ge, B? H? is an electron deficient hydride and HF is electron rich.
Which of the following statement is not correct about diborane?
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Which of the following statement is not correct about diborane?
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In diborane the boron atoms are sp³ hybridized.
In one molal solution that contains 0.5 mole of a solute, there is:
In one molal solution that contains 0.5 mole of a solute, there is:
Molality = moles of solute / mass of solvent (kgs) ⇒ 1 = 0.5 / W (kgs)
Wsolvent (kgs) = 0.5 = 500 g
Given below are two statements:
Statement I:
The boiling points of the following hydrides of group 16 elements increases in the order- H₂O < H₂S < H₂Se < H₂Te
Statement II:
The boiling points of these hydrides increase with increase in molar mass.
In the light of the above statements, choose the most appropriate answer from the options given below:
Given below are two statements:
Statement I:
The boiling points of the following hydrides of group 16 elements increases in the order- H₂O < H₂S < H₂Se < H₂Te
Statement II:
The boiling points of these hydrides increase with increase in molar mass.
In the light of the above statements, choose the most appropriate answer from the options given below:
The boiling point order is: H? S < H? Se < H? Te < H? O
Carbon atoms in diamond are sp³ hybridized and those in graphite are sp² hybridized.
Match List- I with List-II
List -I
(a) Li
(b) Na
(c) KOH
(d) Cs
List-II
(i) absorbent for carbon dioxide
(ii) electrochemical cells
(iii) coolant in fast breeder reactors
(iv) photoelectric cell
Choose the correct answer from the options given below:
Match List- I with List-II
List -I
(a) Li
(b) Na
(c) KOH
(d) Cs
List-II
(i) absorbent for carbon dioxide
(ii) electrochemical cells
(iii) coolant in fast breeder reactors
(iv) photoelectric cell
Choose the correct answer from the options given below:
Li is used in making batteries, liquid Na is a coolant in nuclear reactors. Cs is used in photoelectric cells and KOH as a base is used to absorb acidic oxides like CO?
The IUPAC name of an element with atomic number 119 is:
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The IUPAC name of an element with atomic number 119 is:
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IUPAC name of element with atomic number 119 is ununennium.
The oxidation state of K in KO? is (+1).
Given below are two statements:
Statement I : H2O2 can act as both oxidizing and reducing agent in basic medium.
Statement II: In the hydrogen economy, the energy is transmitted in the form of dihydrogen.
In the light of the above statements, choose the correct answer from the options given below:
Given below are two statements:
Statement I : H2O2 can act as both oxidizing and reducing agent in basic medium.
Statement II: In the hydrogen economy, the energy is transmitted in the form of dihydrogen.
In the light of the above statements, choose the correct answer from the options given below:
H? O? can act as both an oxidizing & reducing agent in both acidic & basic medium. In the hydrogen economy, energy is stored & transmitted in the form of dihydrogen.