Ncert Solutions Chemistry Class 11th
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Keep it short & simple. Type complete word. Avoid abusive language.
The green house gas/es is (are) :
(A) Carbon dioxide
(B) Oxygen
(C) Water vapour
(D) Methane
Choose the most appropriate answer from the options given below:
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The green house gas/es is (are) :
(A) Carbon dioxide
(B) Oxygen
(C) Water vapour
(D) Methane
Choose the most appropriate answer from the options given below:
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Oxygen gas (O? ) is not considered a greenhouse gas.
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Statement I: Sodium hydride can be used as an oxidizing agent.
Statement II: The lone pair of electrons on nitrogen in pyridine makes it basic.
Choose the CORRECT answer from the options given below:
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Statement I: Sodium hydride can be used as an oxidizing agent.
Statement II: The lone pair of electrons on nitrogen in pyridine makes it basic.
Choose the CORRECT answer from the options given below:
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In sodium hydride (NaH), hydrogen has an oxidation state of -1. In this state, it can only act as a reducing agent.
Upvote The oxidation states of nitrogen in NO, NO?, N?O and NO? are in the order of:
The oxidation states of nitrogen in NO, NO?, N?O and NO? are in the order of:
Oxidation state of N
| NO | +2 |
|-|-|
| NO? | +4 |
| N? O | +1 |
| NO? | +5 |
So, order of oxidation state is
NO? > NO? > NO > N? O
Upvote Mn? O? is mixed oxide which contains MnO and Mn? O? , so Mn is in +2 and +3 oxidation state respectively. Both Mn? ² & Mn³? has unpaired electrons so Mn? O? will show magnetic property. While all other oxides have no unpaired electrons either on cation or on anion.
Upvote Match List – I with List – II:
| List – I | List – II |
| :--- | :--- |
| (a) Be | (i) Treatment of cancer |
| (b) Mg | (ii) Extraction of metals |
| (c) Ca | (iii) Incendiary bombs and signals |
| (d) Ra | (iv) Windows of X-ray tubes |
| | (v) Bearings for motor engines. |
Choose the most appropriate answer from the option given below:
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Match List – I with List – II:
| List – I | List – II |
| :--- | :--- |
| (a) Be | (i) Treatment of cancer |
| (b) Mg | (ii) Extraction of metals |
| (c) Ca | (iii) Incendiary bombs and signals |
| (d) Ra | (iv) Windows of X-ray tubes |
| | (v) Bearings for motor engines. |
Choose the most appropriate answer from the option given below:
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Be is used in X ray tube windows.
Mg is used in incendiary bombs & signals.
Compounds of Ca i.e CaCO? is used in extraction of metals like Fe.
Radium (Ra) is used in treatment of cancer in radiotherapy.
Upvote _____ grams of 3-Hydroxy propanal (MW = 74) must be dehydrated to produce 7.8g of acrolein (MW = 56) (C?H?O) if the percentage yield is 64. (Round off to the nearest integer).
[Given: Atomic masses: C: 12.0u, H:1.0u, O:16.0u]
_____ grams of 3-Hydroxy propanal (MW = 74) must be dehydrated to produce 7.8g of acrolein (MW = 56) (C?H?O) if the percentage yield is 64. (Round off to the nearest integer).
[Given: Atomic masses: C: 12.0u, H:1.0u, O:16.0u]
3-Hydroxy propanal
If 7.8g of C? H? O (molar mass 56 g/mol ) is formed, calculate the initial weight of 3-hydroxy propanal (molar mass 74 g/mol ).
Weight = (7.8/56) × 74 × (100/64) [Assuming 64% yield, though the number seems out of place].
Ans ≈ 16 g.
Upvote AX is a covalent diatomic molecule where A and X are second row elements of periodic table. Based on molecular orbital theory, the bond order of AX is 2.5. The total number of electrons in AX is _____. (Round off to the nearest integer).
AX is a covalent diatomic molecule where A and X are second row elements of periodic table. Based on molecular orbital theory, the bond order of AX is 2.5. The total number of electrons in AX is _____. (Round off to the nearest integer).
AX is a diatomic molecule with a bond order of 2.5.
The compound is NO. The total number of electrons = 15 (7+8).
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The Kjeldahl method is not applicable for nitrogen estimation in:
Compounds containing nitrogen in a nitro group.
Compounds containing an Azo group.
Pyridine.
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Considering the above chemical reaction, identify the product "X":
Considering the above chemical reaction, identify the product "X":
The addition of HBr to H? C−CH? −CH=CH? proceeds via carbocation formation.
Formation of a 1° Carbocation (A): H? C−CH?
Formation of a 2° Carbocation (B): H? C−CH? −C? H−CH?
The 2° carbocation (B) is more stable than the 1° carbocation (A). Therefore, the activation energy (Ea) for the formation of B
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