Ncert Solutions Chemistry Class 11th
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New answer posted
7 months agoContributor-Level 9
Bismuth (Bi) is a metal in group 15. Its hydride is BiH? , which is the strongest reducing agent due to its the lowest thermal stability.
New answer posted
7 months agoContributor-Level 9
Hydrated halides of group 2 from Ca onwards undergo dehydration on heating. But the hydrated halide of Mg, i.e., MgCl? ·8H? O, does not undergo dehydration on heating but undergoes hydrolysis.
BeO is amphoteric, while other oxides of group 2 are basic in nature.
New answer posted
7 months agoContributor-Level 9
Oxidation States (O.S) of Phosphorus (P):
- Hypophosphorous acid – H? PO? : +1
- Orthophosphoric acid – H? PO? : +5
- Hypophosphoric acid – H? P? O? : +4
- Orthophosphorous acid – H? PO? : +3
New answer posted
7 months agoContributor-Level 9
Formation of photochemical smog, which is also known as oxidizing smog, takes place in the presence of sunlight and O?
New answer posted
7 months agoContributor-Level 9
(a) Haber's process is used for the synthesis of NH?
(b) Ostwald's process is used to synthesize HNO?
(c) Contact process is used for the synthesis of H? SO?
(d) Hall-Héroult process is used for the extraction of aluminium.
New answer posted
7 months agoContributor-Level 10
The reaction is Fe (s) + 2HCl (aq) → FeCl? (aq) + H? (g). 50 g of Fe corresponds to 0.89 moles, which produces 0.89 moles of H? (g). The work done by the gas is calculated using W = -Δn_gasRT. The work done by the gas is the positive value, 2218 J.
Answer: 2218 J
New answer posted
7 months agoContributor-Level 10
This problem involves the stoichiometry of acid-base neutralization.
o For the reaction with H? PO? (a dibasic acid), 100 mL of NaOH is required.
o For the reaction with H? PO? (a monobasic acid), 200 mL of NaOH is required.
New answer posted
7 months agoContributor-Level 9
ΔG° = + 25.2 kJ / mol
Using ΔG° = -2.3 RT log Kp
25.2 * 10³ = - 2.3 * 8.3 * 400 log Kp
o 3.3 = log Kp
log (1 / 2*10³) = log Kp
Kp = 1 / (2*10³)
Using; Kp = Kc (RT)
1 / (2*10³) = Kc (0.083 * 400)? ¹
New answer posted
7 months agoContributor-Level 10
Iron (III) iodide (FeI? ) does not exist because it is unstable. The Fe³? ion is a strong enough oxidizing agent to be easily reduced to Fe²? by the I? ion, which in turn is oxidized.
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