Ncert Solutions Chemistry Class 11th

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7 months ago

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R
Raj Pandey

Contributor-Level 9

Bismuth (Bi) is a metal in group 15. Its hydride is BiH? , which is the strongest reducing agent due to its the lowest thermal stability.

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7 months ago

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R
Raj Pandey

Contributor-Level 9

Hydrated halides of group 2 from Ca onwards undergo dehydration on heating. But the hydrated halide of Mg, i.e., MgCl? ·8H? O, does not undergo dehydration on heating but undergoes hydrolysis.
BeO is amphoteric, while other oxides of group 2 are basic in nature.

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Raj Pandey

Contributor-Level 9

Oxidation States (O.S) of Phosphorus (P):

  • Hypophosphorous acid – H? PO? : +1
  • Orthophosphoric acid – H? PO? : +5
  • Hypophosphoric acid – H? P? O? : +4
  • Orthophosphorous acid – H? PO? : +3

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Raj Pandey

Contributor-Level 9

Formation of photochemical smog, which is also known as oxidizing smog, takes place in the presence of sunlight and O?

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Raj Pandey

Contributor-Level 9

(a) Haber's process is used for the synthesis of NH?
(b) Ostwald's process is used to synthesize HNO?
(c) Contact process is used for the synthesis of H? SO?
(d) Hall-Héroult process is used for the extraction of aluminium.

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7 months ago

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A
alok kumar singh

Contributor-Level 10

The reaction is Fe (s) + 2HCl (aq) → FeCl? (aq) + H? (g). 50 g of Fe corresponds to 0.89 moles, which produces 0.89 moles of H? (g). The work done by the gas is calculated using W = -Δn_gasRT. The work done by the gas is the positive value, 2218 J.
Answer: 2218 J

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7 months ago

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A
alok kumar singh

Contributor-Level 10

This problem involves the stoichiometry of acid-base neutralization.

o   For the reaction with H? PO? (a dibasic acid), 100 mL of NaOH is required.

o   For the reaction with H? PO? (a monobasic acid), 200 mL of NaOH is required.

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A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

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R
Raj Pandey

Contributor-Level 9

ΔG° = + 25.2 kJ / mol
Using ΔG° = -2.3 RT log Kp
25.2 * 10³ = - 2.3 * 8.3 * 400 log Kp

o   3.3 = log Kp
log (1 / 2*10³) = log Kp
Kp = 1 / (2*10³)
Using; Kp = Kc (RT)
1 / (2*10³) = Kc (0.083 * 400)? ¹

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7 months ago

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alok kumar singh

Contributor-Level 10

Iron (III) iodide (FeI? ) does not exist because it is unstable. The Fe³? ion is a strong enough oxidizing agent to be easily reduced to Fe²? by the I? ion, which in turn is oxidized.

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