Ncert Solutions Chemistry Class 11th
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Which of the following attain the linear structure:
(i) BeCl2
(ii) NCO+
(iii) NO2
(iv) CS2
Which of the following attain the linear structure:
(i) BeCl2
(ii) NCO+
(iii) NO2
(iv) CS2
This is a Multiple Choice Questions as classified in NCERT Exemplar
Ans: Option (i) and (iv)

In the following questions two or more options may be correct.
Which of the following have identical bond order?
(i) CN–
(ii) NO+
(iii) O2–
(iv) O22–
In the following questions two or more options may be correct.
Which of the following have identical bond order?
(i) CN–
(ii) NO+
(iii) O2–
(iv) O22–
This is a Multiple Choice Questions as classified in NCERT Exemplar
Ans: Option (i) and option (ii)
Bond order depends on the electronic configuration of the molecular species, and the electronic configuration depends on the number of electrons a particular atom is contributing in its molecular struct
Amongst the following elements whose electronic configurations are given below, the one having the highest ionisation enthalpy is
(i) [Ne]3s2 3p1
(ii) [Ne]3s2 3p3
(iii) [Ne]3s2 3p2
(iv) [Ar]3d104s24p3
Amongst the following elements whose electronic configurations are given below, the one having the highest ionisation enthalpy is
(i) [Ne]3s2 3p1
(ii) [Ne]3s2 3p3
(iii) [Ne]3s2 3p2
(iv) [Ar]3d104s24p3
This is a Multiple Choice Questions as classified in NCERT Exemplar
Ans: Option (ii)
Aluminium has [Ne]3s2 3p1 electronic configuration. Phosphorus has [Ne]3s2 3p3. The electronic configuration of silicon is [Ne]3s2 3p2 and the electronic configuration of arsenic is [Ar]3d104s24p3.
Ioni
The electronic configuration of the outer most shell of the most electronegative element is
(i) 2s22p5
(ii) 3s23p5
(iii) 4s24p5
(iv) 5s25p5
The electronic configuration of the outer most shell of the most electronegative element is
(i) 2s22p5
(ii) 3s23p5
(iii) 4s24p5
(iv) 5s25p5
This is a Multiple Choice Questions as classified in NCERT Exemplar
Ans: Option (i)
The most electronegative element in the periodic table is fluorine having an atomic number 9 . The electronic configuration of fluorine is 1s2 2s2 2p5. Hence, the electronic configuration of the outermost shell of fluo
Which of the following options represents the correct bond order :
(i) O2– > O2 > O2+
(ii) O2 – < O2 < O2 +
(iii) O2 – > O2 < O2+
(iv) O2– < O2 > O2+
Which of the following options represents the correct bond order :
(i) O2– > O2 > O2+
(ii) O2 – < O2 < O2 +
(iii) O2 – > O2 < O2+
(iv) O2– < O2 > O2+
This is a Multiple Choice Questions as classified in NCERT Exemplar
Ans: Option (ii)
The electronic configurations and the bond orders of the given species are given below:
Bond order of O2 - : σ1s2 σ∗1s2 σ2s2 σ∗2s2 σ2p2z (π2p2x = π2p2y) (π∗2p1x= π∗2p1y)
Bond order = ( Nb- Na)
BO= (10-7)= = 1.5
Bond
Which of the following statement is not correct from the view point of molecular orbital theory?
(i) Be2 is not a stable molecule.
(ii) He2 is not stable but He2 + is expected to exist.
(iii) Bond strength of N2 is maximum amongst the homonuclear diatomic molecules belonging to the second period.
(iv) The order of energies of molecular orbitals in N2 molecule is
σ2s < σ* 2s < σ2pz < (π2px = π2py ) < (π*2px = π* 2py) < σ* 2pz
Which of the following statement is not correct from the view point of molecular orbital theory?
(i) Be2 is not a stable molecule.
(ii) He2 is not stable but He2 + is expected to exist.
(iii) Bond strength of N2 is maximum amongst the homonuclear diatomic molecules belonging to the second period.
(iv) The order of energies of molecular orbitals in N2 molecule is
σ2s < σ* 2s < σ2pz < (π2px = π2py ) < (π*2px = π* 2py) < σ* 2pz
This is a Multiple Choice Questions as classified in NCERT Exemplar
Ans: Option (iv)
(a) A molecule which has a zero bond order never exists and a molecule having a non-zero bond order either exists or is expected to exist.
(b) If the value of bond order is high then the bond strength will also be hi
Which of the following order of energies of molecular orbitals of N2 is correct?
(i) (π2py ) < (σ2pz ) < (π* 2px) ≈ (π*2py)
(ii) (π2py ) > (σ2pz ) > (π* 2px ) ≈ (π*2py )
(iii) (π2py ) < (σ2pz ) > (π* 2px) ≈ (π*2py )
(iv) (π2py ) > (σ2pz ) < (π* 2px ) ≈ (π*2py )
Which of the following order of energies of molecular orbitals of N2 is correct?
(i) (π2py ) < (σ2pz ) < (π* 2px) ≈ (π*2py)
(ii) (π2py ) > (σ2pz ) > (π* 2px ) ≈ (π*2py )
(iii) (π2py ) < (σ2pz ) > (π* 2px) ≈ (π*2py )
(iv) (π2py ) > (σ2pz ) < (π* 2px ) ≈ (π*2py )
This is a Multiple Choice Questions as classified in NCERT Exemplar
Ans: Option (iv)
In the molecules of boron ( B2 ), carbon ( C2 ) and nitrogen ( N2 ) the energy of s2pz molecular orbital is greater than the energy of P2px and P2py molecular orbital.
So, the correct order of energies of molecul
The bond between B and C will be
(i) Ionic
(ii) Covalent
(iii) Hydrogen
(iv) Coordinate
The bond between B and C will be
(i) Ionic
(ii) Covalent
(iii) Hydrogen
(iv) Coordinate
This is a Multiple Choice Questions as classified in NCERT Exemplar
Ans: Option (ii)
The element B represents the electronic configuration of phosphorus atom and element C represents the electronic configuration of chlorine atom. Both phosphorus and chlorine are non-metals hence the bonding forming be
The molecular formula of the compound formed from B and C will be:
(i) BC
(ii) B2C
(iii) BC2
(iv) BC3
The molecular formula of the compound formed from B and C will be:
(i) BC
(ii) B2C
(iii) BC2
(iv) BC3
This is a Multiple Choice Questions as classified in NCERT Exemplar
Ans: Option (iv)
The electronic configuration of B given as 1S2 2S2 2P6 3S2 3P3 which represents phosphorous atom. The electronic configuration of C is given as 1S2 2S2 2P6 3S2 3P5 which represents chlorine mol
Stable form of C may be represented by the formula :
(i) C
(ii) C2
(iii) C3
(iv) C4
Stable form of C may be represented by the formula :
(i) C
(ii) C2
(iii) C3
(iv) C4
This is a Multiple Choice Questions as classified in NCERT Exemplar
Ans: Option (ii)
The electronic configuration of C is given 1S2 2S2 2P6 3S2 3P5 which the electronic configuration of chlorine atom ( Cl ). It is unstable due to one unpaired electron in the p-subshell. Hence, the C2 will