Ncert Solutions Chemistry Class 11th

Get insights from 2k questions on Ncert Solutions Chemistry Class 11th, answered by students, alumni, and experts. You may also ask and answer any question you like about Ncert Solutions Chemistry Class 11th

Follow Ask Question
2k

Questions

0

Discussions

12

Active Users

29

Followers

New answer posted

5 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

This is a Long Answer Type Questions as classified in NCERT Exemplar

Ans: According to Le Chatelier's principle, when we raise the temperature, it shifts the equilibrium to left and decreases the equilibrium concentration of ammonia since it is an exothermic reaction. In other words, low temperature and high pressure is favourable for high yield of ammonia. There will be no change in equilibria on addition of argon (Ar).

New answer posted

5 months ago

0 Follower 1 View

V
Vishal Baghel

Contributor-Level 10

This is a Long Answer Type Questions as classified in NCERT Exemplar

Ans: The values of Kc and Qc are itself sufficient to explain the direction of reaction and less than or greater than one another decides the direction in which reaction will proceed as follows-

(i) As Qc < Kc, the reaction proceeds in the forward direction. 

(ii) If Qc > Kc, the reaction will proceed in the direction of reactants (reverse reaction). 

(iii) If Qc = Kc, no net reaction occurs.

New answer posted

5 months ago

0 Follower 5 Views

P
Payal Gupta

Contributor-Level 10

This is a long answer type question as classified in NCERT Exemplar

Hydrogen peroxide is produced by acidifying barium peroxide and eliminating surplus water by evaporation under low pressure. Water is used to extract it, then distillation under lower pressure concentrates it to around 30% (by mass). Careful distillation under low pressure can increase the concentration to 85%. To achieve pure H2O2, the residual water can be frozen out.

Uses of H2O2:

(i) As an antiseptic it is sold in the market as perhydrol.

(ii) It is used to manufacture chemicals like sodium perborate and per - carbonate. It is employed in the industries as a bleachin

...more

New answer posted

5 months ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

This is a long answer type question as classified in NCERT Exemplar

D2O can be prepared by prolonged electrolysis of water. Due to high molecular mass D2O differs from water.

NaOH+D2O → NaOD+HOD

HCl+D2O → DCl+ HOD

NH4Cl+D2O → NH3DCl+HOD

Physical Properties of H2O and D2O

Property 

H2O

D2O

Molecular mass (g mol-1)

18.015

20.0276

Melting point/K         

273.0  

276.8

Boiling point/K          

373.0  

374.4

Enthalpy of formation/kJ mol-1

-285.9 

-294.6

Enthalpy of Vaporisation (373 K)/kJ mol-1

40.66  

41.61

Enthalpy of fusion/kJ mol-1

6.01    

Temp of max. density/K        

276.98

284.2

Density (298 K)/g cm-3         

1.0000

1.1059

Viscosity/centipoise  

0.8903

1.107

Dielectric constant

78.39  

78.06

New answer posted

5 months ago

0 Follower 1 View

P
Payal Gupta

Contributor-Level 10

This is a long answer type question as classified in NCERT Exemplar

Atomic hydrogen is highly reactive, whereas molecular hydrogen is rather inert. Bond dissociation enthalpy determines the chemical behaviour of dihydrogen (and, for that matter, any molecule) to a great extent. For a single bond between two atoms of any element, the H-H bond dissociation enthalpy is the highest. As a result, molecular hydrogen reacts only with a few elements.

New answer posted

5 months ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

This is a long answer type question as classified in NCERT Exemplar

Atomic hydrogen is highly reactive, whereas molecular hydrogen is rather inert. Bond dissociation enthalpy determines the chemical behaviour of dihydrogen (and, for that matter, any molecule) to a great extent. For a single bond between two atoms of any element, the H-H bond dissociation enthalpy is the highest. As a result, molecular hydrogen reacts only with a few elements.

New answer posted

5 months ago

0 Follower 1 View

V
Vishal Baghel

Contributor-Level 10

This is a Assertion Type Questions as classified in NCERT Exemplar

Ans: Option (iv)

Both the statements given in the assertion and reason are false.

The energy required to break the first O-H bond is not same than that of the second O-H bond in water molecule, that means the bond enthalpies of the two O-Hare different. This is because the electronic environment around the oxygen atom in water molecules is not the same even after the O-H bond breaks.

New answer posted

5 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

This is a Assertion Type Questions as classified in NCERT Exemplar

Ans: Option (i)

The statements given in the assertion and reason, both are correct and the reason given is the correct explanation for the assertion. In NH3 only one lone pair of electron is present and due to that lone pair-bond pair repulsion occurs which forms a distorted tetrahedral geometry (pyramidal) .

In H2O two lone pairs of electrons are present on the oxygen atom and due to this lone pairlone pair repulsion occurs which shifts the bonds and forms a bent geometry. The lone pair-lone pair repulsion is more than the lone pair-bond pair repulsion. Thus, bond angle i

...more

New answer posted

5 months ago

0 Follower 1 View

V
Vishal Baghel

Contributor-Level 10

This is a Assertion Type Questions as classified in NCERT Exemplar

Ans: Option (i) 

Both the statements given in assertion and reason are correct and the reason given is the correct explanation for the assertion. The sodium chloride formed by the action of chlorine gas on the sodium metal has a complete octet. The valence shells of both the atoms are fulfilled, that is why attains an octet.

New answer posted

5 months ago

0 Follower 1 View

V
Vishal Baghel

Contributor-Level 10

This is a Matching Type Questions as classified in NCERT Exemplar

Ans:

(i) Tetrahedral    (c) sp3

(ii) Trigonal    (a) sp2

(iii) Linear    (b)sp

 

Explanation :-

(i) A tetrahedral molecule has four electron pairs and these make sigma bonds with each other. The s and p orbitals overlap with each other thus forming a sp3 hybridized molecule.

(ii) There are two possibilities for the central atom to have sp2 Either all the bonds are in place i.e, the bond pairs are all sigma bonds or pi bonds or there are only two bonds and one lone pair of electrons.

(iii) The sp hybridization involves the mixing of the val

...more

Get authentic answers from experts, students and alumni that you won't find anywhere else

Sign Up on Shiksha

On Shiksha, get access to

  • 65k Colleges
  • 1.2k Exams
  • 679k Reviews
  • 1800k Answers

Share Your College Life Experience

×
×

This website uses Cookies and related technologies for the site to function correctly and securely, improve & personalise your browsing experience, analyse traffic, and support our marketing efforts and serve the Core Purpose. By continuing to browse the site, you agree to Privacy Policy and Cookie Policy.