Ncert Solutions Chemistry Class 12th
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10 months agoContributor-Level 10
8.23 In transition metals, it can be observed that the oxidation state of the metal varies from +1 to +7 which is obtained by removing all its valence electrons. In transition elements the oxidation state differ by 1 unlike non transition elements whose oxidation state differs by 2, for example in transition metals (Cu2+, Cu3+ and Fe2+, Fe3+) and In non-transition elements, this variation is selective, always differing by 2, e.g. S exhibits +2, +4, +6 oxidation states and N exhibits +3, + 5, etc.

New answer posted
10 months agoContributor-Level 10
8.22 Interstitial compounds are those compounds in which small atomic size elements like H, C, N occupy the interstitial sites of the crystal lattice of the Transition metal due to their large size.
Example, in the diagram given below:

Here, Green Balls form the Crystal lattice of transition metal and Blue balls represent elements like H/C/N which occupy the interstitial sites.
New answer posted
10 months agoContributor-Level 10
8.21 (i) Transition metals and many of their compounds show paramagnetic behavior- Paramagnetic behaviour is shown by transition metals as paramagnetism is due to the presence of unpaired electrons which have a magnetic moment associated with its spin and angular momentum, as the orbital angular momentum is satisfied in the first transition series. So the paramagnetic is only due to the unpaired electrons.
(ii) The enthalpies of atomisation of the transition metals are high- Enthalpies of atomization is the enthalpy change when 1 mol of gaseous atoms is formed from its element in its defined physical state under standard cond
New answer posted
10 months agoContributor-Level 10
8.20 +3 oxidation state is the most common oxidation state of lanthanides i.e., Ln (III) compounds are predominant. +2 and +4 oxidation states can also be found in the solution or in solid compounds, but are not predominant.
New answer posted
10 months agoContributor-Level 10
8.19 Transition metals have a partially filled d−orbital. Therefore, the electronic configuration of transition elements is (n−1) d1-10 ns0-2 The non-transition elements either do not have a partially filled d−orbital. Therefore, the electronic configuration of non-transition elements is ns1-2 orns2 np1-6.
New answer posted
10 months agoContributor-Level 10
8.18 Transition elements are those elements in which the atoms or ions (in stable oxidation state) contain partially filled d-orbital. These elements in the d-block show a transition of properties between s-block and p-block. Therefore, these are called transition elements. Elements such as Zn, Cd, and Hg cannot be classified as transition elements because these have completely filled d-subshell.
New answer posted
10 months agoContributor-Level 10
8.17 On moving along the lanthanoid series, the atomic number increases. Also, with the increase in atomic number, the number of electrons in the 4f orbital also increases.
The 4f electrons have a poor shielding effect. Therefore, the effective nuclear charge experienced by the outer electrons increases. Consequently, the force of attraction between the nucleus and valence electrons increases. This results in a decrease in the size of lanthanoids with the increase in the atomic number. This is termed as lanthanoid contraction.
CONSEQUENCES:
1. The properties of second and third transition series are similar in
2. Separation of lanthan
New answer posted
10 months agoContributor-Level 10
7.30
Two poisonous gases that can be prepared with chlorine gas are:
Phosgene (COCl2)
This is how phosphene is formed:
CO + Cl2? COCl2 (in presence of sunlight)
(ii) Mustard gas (Cl-C2H4-S-C2H4-Cl)
(iii) Tear gas (CCl3NO2)
New answer posted
10 months agoContributor-Level 10
7.29
Moist chlorine is a good reducing agent because it can accept electrons from other species as it is very electronegative.
(iii) The bleaching action of chlorine is due to oxidation by nascent oxygen produced. This nascent oxygen can be produced by
Chlorine dissolves in water in absence of sunlight and forms hydrochloric acid and hypochlorous acid (HOCl)
Since hypochlorous acid is not much stable it decomposes giving nascent oxygen. Cl2 + H2O HCl + HOCl
HOCl HCl + [O]
This [O] is called as nascent oxygen. This nascent oxygen is responsible for bleaching action.
NOTE: Since chlorine has the ability to kill harmful micro-organism it
New answer posted
10 months agoContributor-Level 10
7.28
Sea water is a treasure of many elements and halogens are one of them. It contains many compounds of halogen including bromides, iodides, and chlorides. The solid deposits from sea water contain NaCl and Carnalite.
It primarily contains COMMON SALT (2.5% by mass). The deposits of dried up sea bed also contain sodium chloride and Carnallite, KCl.MgCl2.6H2O .
The Marine life also contains iodine in their systems. For example, sea weed may contain 0.5% iodine as sodium iodide (NaI) and Chile saltpetre (sodium compound) contains about 0.3% of sodium iodate. Thus, the sea is the greatest source of halogens.
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