Ncert Solutions Chemistry Class 12th

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alok kumar singh

Contributor-Level 10

Inversion of Sucrose:
C? H? O? (Sucrose) + H? O - (Invertase)-> C? H? O? (Glucose) + C? H? O? (Fructose)

Fermentation of Glucose:
C? H? O? (Glucose) - (Zymase)-> 2C? H? OH (Ethanol) + 2CO?

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alok kumar singh

Contributor-Level 10

KMnO? oxidizes alkanes that contain a tertiary hydrogen (3°H) to form tertiary alcohols.

n-alkanes, which do not contain tertiary hydrogens, are not oxidized by KMnO? under these conditions.

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alok kumar singh

Contributor-Level 10

Co (NH? )? ] [Cr (CN)? ]: Co-ordination isomerism

[Co (NH? )? (NO? )? ]: Linkage isomerism

[Cr (H? O)? ]Cl? : Solvate isomerism

Cis- [CrCl? (Ox)? ]³? : Optical isomerism

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alok kumar singh

Contributor-Level 10

CN? and NO? are examples of ambident nucleophiles.

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Raj Pandey

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o   Chlorophyll: Magnesium present in chlorophyll.

o   Vitamin B? : Cobalt (cyanocobalamin).

o   Anticancer drug: Platinum (Coordination compound of platinum).

o   Grubbs catalyst: Ruthenium.

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Raj Pandey

Contributor-Level 9

When we add cryolite (Na? AlF? ) in the extraction of aluminium, the melting point of alumina decreases

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Raj Pandey

Contributor-Level 9

Functional group isomers

 

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alok kumar singh

Contributor-Level 10

Haematite: Fe? O?

Bauxite: Al? O? ·xH? O

Magnetite: Fe? O?

Malachite: CuCO? ·Cu (OH)?

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Raj Pandey

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Reaction Sequence:

o   NO? + CH? COOH → HNO? + CH? COO?

o   Sulphanilic acid (+ NH? CH? COO? ) + HNO? → N-acetylated diazonium intermediate + 2H? O

The intermediate + another molecule → Red Azodye + NH? + CH? COOH

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alok kumar singh

Contributor-Level 10

100 mol of KBr is doped with 10? mol of SrBr?

Therefore, 1 mol of KBr contains 10? mol of SrBr?

Molar mass of KBr = 119 g/mol .

119 g of KBr contains 10? mol of SrBr?

1 g of KBr contains (10? / 119) mol of SrBr?

Each Sr²? ion introduced creates one cation vacancy to maintain electrical neutrality.

Number of cation vacancies = (moles of SrBr? ) * (Avogadro's number)

Number of vacancies = (10? / 119) * (6.023 * 10²³) = 5.06 * 10¹?

The answer provided in the document is "5 (Rounded off)", which likely refers to the coefficient 5.06.

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