Ncert Solutions Chemistry Class 12th

R-CONH? + Br? + 4NaOH → R-NH? + 2NaBr + Na? CO? + 2H? O
This reaction is the Hoffmann bromamide degradation, in which an amide is converted to a 1° amine.

Kindly consider the following Image 

The E° value for Ce? /Ce³? is +1.74 V, which suggests that Ce? is a strong oxidant, reverting to its common +3 oxidation state. So, Ce³? is more stable than Ce?

The size of the Bk³? ion is less than the Np³? ion because Berkelium (Bk) lies beyond Neptunium (Np) in the actinoid series, and the size variation here is because of the actinoid contraction.

The enol form of acetone exists in less than 0.1% quantity, since its keto form is highly stable. But in the case of acetylacetone, the enol form is stabilized by intramolecular H-bonding, so its quantity increases to approximately 15%.
The intramolecular H-bond in the enol form of acetylacetone is shown.

DIBAL-H at low temperature in a non-polar solvent, followed by hydrolysis, reduces esters to an aldehyde and an alcohol as a byproduct. The reaction shown is:

Kindly consider the following Image 

First, the number of unit cells in the given mass is determined. In an HCP structure, there are 6 atoms and 18 total voids (6 octahedral + 12 tetrahedral) per unit cell. Multiplying the number of unit cells by 18 gives the total number of voids. The result is14.9 x 10²¹, which is rounded.

Urea-formaldehyde resin is used for wood laminates because of its durable and unbreakable properties.

Solubility of CdSO? is water ; S = 8 * 10? M
Using Ksp = S²
Ksp = 64 * 10? M
Now,
CdSO? Cd²? + SO? ²?
in H? SO? (0.01M)
Ksp = [Cd²? ] [SO? ²? ]
64 * 10? = S? (S? + 0.01)
S? << 0.01
So, S? = 64 * 10? M.