P Block Elements
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Which of the following acids forms three series of salts?
(i) H3PO2
(ii) H3BO3
(iii) H3PO4
(iv) H3PO3
Which of the following acids forms three series of salts?
(i) H3PO2
(ii) H3BO3
(iii) H3PO4
(iv) H3PO3
This is a multiple choice answer as classified in NCERT Exemplar
Correct option is (iii) H3PO4
When it reacts with a metal atom, it can produce three different forms of salts, referred known as the three series of salts.
H3PO4 + Na→NaH2PO4
NaH2PO4 + Na→Na2HPO4
Na2HPO4 + Na→Na3PO4
Upvote 
On heating with concentrated NaOH solution in an inert atmosphere of CO2, white phosphorus gives a gas. Which of the following statements is incorrect about the gas?
(i) It is highly poisonous and smells like rotten fish.
(ii) It’s solution in water decomposes in the presence of light.
(iii) It is more basic than NH3.
(iv) It is less basic than NH3.
On heating with concentrated NaOH solution in an inert atmosphere of CO2, white phosphorus gives a gas. Which of the following statements is incorrect about the gas?
(i) It is highly poisonous and smells like rotten fish.
(ii) It’s solution in water decomposes in the presence of light.
(iii) It is more basic than NH3.
(iv) It is less basic than NH3.
This is a multiple choice answer as classified in NCERT Exemplar
Correct option is (iii)
When heated with concentrated NaOH in an inert CO2 environment. It formsPH3
P4 + 3NaOH + 3H2O→PH3 + 3NaH2PO2
As we progress from the top to the bottom in a group, the basic character of hydrides reduces PH
Upvote Bond dissociation enthalpy of E—H (E = element) bonds is given below. Which of the compounds will act as the strongest reducing agent?
Compound NH3 PH3 AsH3 SbH3
Δdiss(E---H)/kJ mol--1 389 322 297 255
(i) NH3
(ii) PH3
(iii) AsH3
(iv) SbH3
Bond dissociation enthalpy of E—H (E = element) bonds is given below. Which of the compounds will act as the strongest reducing agent?
Compound NH3 PH3 AsH3 SbH3
Δdiss(E---H)/kJ mol--1 389 322 297 255
(i) NH3
(ii) PH3
(iii) AsH3
(iv) SbH3
This is a multiple choice answer as classified in NCERT Exemplar
Correct option is (iv)
The E-H bond dissociation energy of SbH3 is the lowest among the aforementioned compounds, it easily releases H, making it a strong reducing agent. The greater the lowering agent, the weaker the E-H bond.
Upvote <p><strong>Bond dissociation enthalpy of E—H (E = element) bonds is given below. Which of the compounds will act as the strongest reducing agent? </strong></p>
<p><strong>Compound NH<sub>3 </sub>PH<sub>3 </sub>AsH<sub>3</sub> SbH<sub>3 </sub></strong></p>
<p><strong>Δdiss(E---H)/kJ mol--1 389 322 297 255</strong></p>
<p><strong>(i) </strong>NH<sub>3</sub></p>
<p><strong>(ii)</strong> PH<sub>3</sub></p>
<p><strong>(iii) </strong>AsH<sub>3</sub></p>
<p><strong>(iv)</strong> SbH<sub>3</sub></p>
Affinity for hydrogen decreases in the group from fluorine to iodine. Which of the halogen acids should have highest bond dissociation enthalpy?
(i) HF
(ii) HCl
(iii) HBr
(iv) HI
Affinity for hydrogen decreases in the group from fluorine to iodine. Which of the halogen acids should have highest bond dissociation enthalpy?
(i) HF
(ii) HCl
(iii) HBr
(iv) HI
This is a multiple choice answer as classified in NCERT Exemplar
Correct option (i)
Fluorine is the most reactive element, forming hydrogen fluoride when it combines with hydrogen gas.
Due to the shorter bond length between the two atoms, it takes a lot of energy to break the link between hydrogen and
Upvote Which of the following pairs of ions are isoelectronic and isostructural?
(i) CO32- , NO3-
(ii) ClO3- , CO32-
(iii) SO32- , NO3-
(iv) ClO3- , SO32-
Which of the following pairs of ions are isoelectronic and isostructural?
(i) CO32- , NO3-
(ii) ClO3- , CO32-
(iii) SO32- , NO3-
(iv) ClO3- , SO32-
This is a multiple choice answer as classified in NCERT Exemplar
Correct option (i)
The compound has the following number of electrons:
NO3- = 32e-
CO32- = 32e-
ClO3- = 42e-
SO3 - = 42e-
Hence, NO3-
Upvote Which of the following elements can be involved in p\pi --d\pi bonding?
(i) Carbon
(ii) Nitrogen
(iii) Phosphorus
(iv) Boron
Which of the following elements can be involved in p\pi --d\pi bonding?
(i) Carbon
(ii) Nitrogen
(iii) Phosphorus
(iv) Boron
This is a multiple choice answer as classified in NCERT Exemplar
Correct option (iii)
If an electron pair is donated to a vacant orbital on one atom and a lone pair of electrons on the other, the bonding is designated pπ-dπ depending on the orbital to which the electron pair is donated and t
Upvote In a cyclotrimetaphosphoric acid molecule, how many single and double bonds are present?
(i) 3 double bonds; 9 single bonds
(ii) 6 double bonds; 6 single bonds
(iii) 3 double bonds; 12 single bonds
(iv) Zero double bonds; 12 single bonds
In a cyclotrimetaphosphoric acid molecule, how many single and double bonds are present?
(i) 3 double bonds; 9 single bonds
(ii) 6 double bonds; 6 single bonds
(iii) 3 double bonds; 12 single bonds
(iv) Zero double bonds; 12 single bonds
This is a multiple choice answer as classified in NCERT Exemplar
Correct option is (iii)
H3PO2, H3PO4, H3PO4, and other oxoacids are formed by phosphorus. P is tetrahedrally surrounded by other atoms in phosphorus oxoacids. At least one P-H bond and an O-H bond are known to form in all of
Upvote In qualitative analysis when H2S is passed through an aqueous solution of salt acidified with dil. HCl, a black precipitate is obtained. On boiling the precipitate with dil. HNO3, it forms a solution of blue colour. Addition of excess of aqueous solution of ammonia to this solution gives _________.
(i) Deep blue precipitate of Cu(OH)2
(ii) Deep blue solution of [Cu(NH3)4]2+
(iii) Deep blue solution of Cu(NO3)2
(iv) Deep blue solution of Cu(OH)2 .Cu(NO3)2
In qualitative analysis when H2S is passed through an aqueous solution of salt acidified with dil. HCl, a black precipitate is obtained. On boiling the precipitate with dil. HNO3, it forms a solution of blue colour. Addition of excess of aqueous solution of ammonia to this solution gives _________.
(i) Deep blue precipitate of Cu(OH)2
(ii) Deep blue solution of [Cu(NH3)4]2+
(iii) Deep blue solution of Cu(NO3)2
(iv) Deep blue solution of Cu(OH)2 .Cu(NO3)2
This is a multiple choice answer as classified in NCERT Exemplar
Correct option (ii)
When H2S is passed through an aqueous solution of salt acidified with dil. HCl in qualitative analysis, a black precipitate is produced. When the precipitate is boiled with dil. HNO3, a blue s
Upvote On addition of conc. H2SO4 to a chloride salt, colourless fumes are evolved but in case of iodide salt, violet fumes come out. This is because
(i) H2SO4 reduces HI to I2
(ii) HI is of violet colour
(iii) HI gets oxidised to I2
(iv) HI changes to HI2O3
On addition of conc. H2SO4 to a chloride salt, colourless fumes are evolved but in case of iodide salt, violet fumes come out. This is because
(i) H2SO4 reduces HI to I2
(ii) HI is of violet colour
(iii) HI gets oxidised to I2
(iv) HI changes to HI2O3
This is a multiple choice answer as classified in NCERT Exemplar
Correct option is (iii)
Hydrogen iodide is a more powerful reducing agent than sulphuric acid, it reduces the amount of iodine in the solution from H2SO4 to SO2 and HI to I2
When chloride salts are treated with sulfuric acid, &n
Upvote