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4 months agoContributor-Level 10
The minimum force F? is calculated as:
F? = (μmg) / √* (1 + μ²)* = ( (1/√3) * 1 * 10 ) / √* (1 + (1/√3)²) = 5N
New answer posted
4 months ago
Contributor-Level 10
Let the charge on C? be q µC. For the capacitor network:
q/C? = (C? * 10 - q) / C? ⇒ q/8 = (2 * 10 - q) / 2 ⇒ q = 16
New answer posted
4 months agoContributor-Level 9
λ? /λ? = (m? v? ) / (m? v? ) ⇒ m? = m? (v? /v? ) (λ? /λ? ) = m? (1/4) (1/2) = (1/8)m?
New answer posted
4 months agoContributor-Level 10
Given the decay equation A = A? e^ (-bt/m):
-bt/m = ln (A/A? )
Solving for b:
b = (-m/t? ) * ln (A/A? ) = (-1 / (2 * 60) * ln (6/12) = 5.775 * 10? ³ kg/s
New answer posted
4 months ago
Contributor-Level 10
Let V? = 10V, V? = xV, V? = 0V, and V? = yV.
Applying Kirchhoff's current law at node B:
(x - 10)/100 + (x - y)/15 + (x - 0)/10 = 0 ⇒ 53x - 20y = 30 . (1)
Applying Kirchhoff's current law at node D:
(y - 10)/60 + (y - x)/15 + (y - 0)/5 = 0 ⇒ 17y - 4x = 10 . (2)
Solving equations (1) and (2), we get:
x = 0.865 and y = 0.792
The current i? is:
i? = (x - y) / 15 = 4.87 mA
New answer posted
4 months agoContributor-Level 10
The bulk modulus B is calculated as:
B = -ΔP / (ΔV/V) = (ρgh) / (ΔV/V) = (10³ * 9.8 * 2 * 10³) / (1.36 * 10? ²) = 1.44 * 10? N/m²
New answer posted
4 months agoContributor-Level 10
The angular frequency ω is calculated as:
ω = 2πf = 2 * 3.14 * 245 = 1.5386 * 10³ rad/s ≈ 1.5 * 10³ rad/s
This continues the solution from number 15 on the previous page.
k = ω / v = (1.53 * 10³) / 300 = 5.1 m? ¹
A = 0.06 / 2 = 0.03m
New answer posted
4 months agoContributor-Level 9
In external magnetic field, a magnetic force acts on every small part of the loop in direction perpendicular to the wire. Thus, loop assumes a shape (circular) in which it covers maximum area
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