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New answer posted

7 months ago

0 Follower 17 Views

R
Raj Pandey

Contributor-Level 9

Apply conservation of momentum along y-axis, we can write
10v? - 10v? sin 30° = 0
⇒ v? = 20m/s

New answer posted

7 months ago

0 Follower 3 Views

R
Raj Pandey

Contributor-Level 9

Deceleration, a = u² / 2S = 10² / (2 * 0.5) = 100 m/s².
Retarding force, F = MA = 0.1 * 100 = 10N

New answer posted

7 months ago

0 Follower 11 Views

R
Raj Pandey

Contributor-Level 9

R_eq = 10 + (50 * 20) / (50 + 20) = 170/7 Ω
⇒ I = 170 / (170/7) = 7A
⇒ x = 10 * 7 = 70V ⇒ Voltage across 10Ω resistor

New answer posted

7 months ago

0 Follower 5 Views

A
alok kumar singh

Contributor-Level 10

The flux φ is calculated as:
φ = (2/5) * 4 * 10³ * 0.4 = 640 Nm²C? ¹

New answer posted

7 months ago

0 Follower 5 Views

A
alok kumar singh

Contributor-Level 10

From the given relations:
mv²/r = |dU/dr| = 4|U? |r³ . (1)
mvr = nh / 2π . (2)
By combining equations (1) and (2), we can derive the radius r:
r = ( (nh)² / (4π√* (U? )*) )¹/³ ⇒ r ∝ n²/³

New answer posted

7 months ago

0 Follower 8 Views

A
alok kumar singh

Contributor-Level 10

4t = 100 * (4/3)π * (40π * 10? * 0.01)³
t = 2.5 * 10? ¹¹ cm = 2.5 * 10? ¹³ m

New answer posted

7 months ago

0 Follower 3 Views

R
Raj Pandey

Contributor-Level 9

1/C = 5/ (ε? * 100) + 5/ (10ε? * 100)
⇒ C = (ε? * 1000) / 55 = (8.85 * 10? ¹² * 1000) / 55 = 1.61 * 10? ¹? F = 161 pF

New answer posted

7 months ago

0 Follower 12 Views

A
alok kumar singh

Contributor-Level 10

Conduction current density, J? = E/ρ = (V/d) / ρ = (V? sin (2πft) / (pd)
Displacement current density, J? = ε (dE/dt) = (ε/d) (dV/dt) = (2πfε/d) * V? cos (2πft)
The ratio of their magnitudes is:
J? / J? = tan (2πft) / (2πfε? ρ) = tan (2π * 900) / (2π * 9 * 10? * 80ε? * 0.25) = 10?

New answer posted

7 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

Electric field squared is proportional to the power P of the bulb (E² ∝ P).
(E' / E)² = (60 / 100) ⇒ E' = E * √* (3/5)*

New answer posted

7 months ago

0 Follower 3 Views

R
Raj Pandey

Contributor-Level 9

Power gain = (i_c² R_c) / (i_b² R_B) = (i_c/i_b)² (R_c/R_B) = (10²)² (10? /10³) = 10?
i_c/i_b = 100 ⇒ β = i_c/i_b = 100

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