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New answer posted
4 months agoContributor-Level 10
The acceleration 'a' is calculated as:
a = (g sinθ) / (1 + I/mr²) = (10 * sin30°) / (1 + 2/5) = 25/7 m/s²
The time 't' is calculated as:
t = 2v / a = (2 * 1) / (25/7) = 0.57 s
New answer posted
4 months agoContributor-Level 10
For an elastic collision where C comes to rest, and the compression in the spring is maximum, the velocities of A and B are equal (v). Using the conservation of mechanical energy:
(1/2)mv? ² = 2 * (1/2)mv² + (1/2)kx²
This gives the maximum compression x as:
x = v? * √* (m / 2k)*
New answer posted
4 months agoContributor-Level 9
From ohm's Law, V = IR = I (ρl / A) = I (ρl / (πd²/4) ⇒ ρ = (πd²V) / (4lI)
Relative error in resistivity,
Δρ/ρ = 2 (Δd/d) + ΔV/V + Δl/l + ΔI/I = 2 * (0.01/5.00) + (0.1/5.0) + (0.1/10.0) + (0.01/2000) = 0.039
Percentage error = (Δρ/ρ) * 100 = 3.9%
New answer posted
4 months agoContributor-Level 9
For constant acceleration, a,
x = ut + (1/2)at² ⇒ x-t graph is parabola.
v = u + at ⇒ v-t graph is straight line with positive slope.
New answer posted
4 months agoContributor-Level 10
The circuit diagram represents an XOR Gate. The output Y is derived as:
Y = (A? B? ) (A + B) = (A? + B? ) (A + B) = A? B + AB? (XOR Gate)
New answer posted
4 months agoContributor-Level 9
Layers of atmosphere are in order of (from bottom) troposphere, stratosphere, mesosphere, thermosphere.
New answer posted
4 months agoContributor-Level 9
Fringe width, β = (λD) / d = (5890 * 10? ¹? * 0.5) / (0.5 * 10? ³) = 589 * 10? m
Distance between first and third bright fringe = 2β = 1178 * 10? m.
New answer posted
4 months agoContributor-Level 9
For adiabatic process CD,
W = (P? V? - P? V? ) / (γ - 1) = (100 * 4 - 200 * 3) / (1.4 - 1) = -500J
New answer posted
4 months agoContributor-Level 9
qE = mg ⇒ neE = (4/3)πr³ρg
⇒ n = (4πr³ρg) / (3eE) = (4 * 3.14 * (2 * 10? ³ )³ * 3 * 10³ * 9.81) / (3 * 1.6 * 10? ¹? * 3.55 * 10? ) = 1.73 * 10¹?
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