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New answer posted

6 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

A = 36 cm2= 36 * 104 m2

? F? =7.2*109N, t=20min.

? F? =ΔPΔt=ECΔtEΔt=? F? cEAΔt=? F? cA

= 0.06 W/cm2

New answer posted

6 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

n1T1+n2T2=nT

(0.1) (200)+ (0.05) (400)= (0.15)T

T=266.67

6.25

New answer posted

6 months ago

0 Follower 8 Views

V
Vishal Baghel

Contributor-Level 10

 VP=8kV, VS=160vP=80kW

(Purely resistive load)

P=VI=VP2RP=VS2RS

RS=VS2P=160*16080*103=320*103=0.32Ω

New answer posted

6 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

1?   (1) ε=3  (2) ε-Ir=2.5VIr=0.5 Now, IR =2.5Rr=5.PRRr=I2RI2r=Rr=5Pr=0.55=0.1

266.67

New answer posted

6 months ago

0 Follower 4 Views

V
Vishal Baghel

Contributor-Level 10

 B1=μ0i2R

B2=μ0iR22 (R2+ (3R)2)3/2=μ0iR22*8R3=μ0i8*2R=B18

B1B2=8:1

New answer posted

6 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10


? v

mv=16mv1

V1=V16

Δk loss =12mv2-12 (16m)V162

12mv21516

% loss =1516*100=93.75%

New answer posted

6 months ago

0 Follower 17 Views

V
Vishal Baghel

Contributor-Level 10

 B=0.5T

FCD=il*B

ilBsin60

=10*5100*0.5*32=38=1.7328

= 0.216 N

New answer posted

6 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

Statement – I

80=ρlA

So, Req=R'4=204=5Ω

Statement – II

P1P2=V22R*3RV2=32

 

New answer posted

6 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

 U? =5jˆ

a? =10iˆ+4jˆ

S? =U? t+12 (a? )t2

20iˆ+y0jˆ=5t2iˆ+5t+2t2jˆ

20=5t2y0=5t+2t2t=218m. 

New answer posted

6 months ago

0 Follower 15 Views

V
Vishal Baghel

Contributor-Level 10

 E=8mev/m

Time to come out, t = 12sec

Vy=at= (eEm)t= (em*8me)*12=4m/s

So,  tan? =VyVx=42

? ? =tan? 12

 

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