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New answer posted

12 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

K=QrΔxΔAT

ML2T-2 (L)L2 (θ) (T)M1L1-T-3θ-1

New question posted

12 months ago

0 Follower 8 Views

New answer posted

12 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

 g=Axx2+a23/2

v0?dV=-x?gdx

O-V=-Axa2+x23/2

Let, a2+x2=t2

2xdx=2tdt

xdx=tdt

V=Atdtt3-At-Aa2+x2x

V = A a 2 + x 2

New answer posted

12 months ago

0 Follower 6 Views

A
alok kumar singh

Contributor-Level 10

ρvg-mg=ma

ρvgm=g+a

m=ρvgg+a

10343π*10-6 (9.8)9.898

4.15gm

New answer posted

12 months ago

0 Follower 9 Views

A
alok kumar singh

Contributor-Level 10

(n) λ=5

(n, m) : Integers

2m+12λ=323/25=2m+12n3n=10m+5

N, m are integers.

So,  m=1, n=5, λ=1

m=4n=15λ=13m=7n=25λ=15

New answer posted

12 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution 

New answer posted

12 months ago

0 Follower 9 Views

A
alok kumar singh

Contributor-Level 10

τ? =μ? *B?

0.018=μ (0.06)sin? 30? μ=0.6 Work =Uf-Ui2μB7.2*10-2J.

New answer posted

12 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

E= (I) (t) (A)cos2? θ
(3.3)2π31.43*10-4*12

0.99*10-4

New answer posted

12 months ago

0 Follower 6 Views

P
Payal Gupta

Contributor-Level 10

C = 10-6 f

f = 0.5 * 103 = 500

z = x R 2 + ( x L x C ) 2                

for minimum impedance :

xL = xC

ω 2 = 1 L C

L = 1 π 2 = 1 1 0 * 1 0 0 0 = 1 0 0 m H                                

New answer posted

12 months ago

0 Follower 6 Views

A
alok kumar singh

Contributor-Level 10

m (L)=m1S1 (ΔT)

m3.4*105= (200) (4200) (25)

m=61.7

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