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New answer posted

12 months ago

0 Follower 14 Views

P
Payal Gupta

Contributor-Level 10

 r=mvqB=2kmqB

2*5*103*1.6*1019*24*1.66*10271.6*1019*12

= 9.975 * 102 cm

= 9.975 cm

New answer posted

12 months ago

0 Follower 6 Views

A
alok kumar singh

Contributor-Level 10

BA=μ0Iθ4πR

BABB=IAθARBIBθBRA

23π2 (4)35π3 [2]

65 .

New answer posted

12 months ago

0 Follower 4 Views

P
Payal Gupta

Contributor-Level 10

U=ncvT

=2*32*R*300=7479J      

New answer posted

12 months ago

0 Follower 3 Views

P
Payal Gupta

Contributor-Level 10

Using newton's law:

2mg – T = 4ma  - (1)

T – mg = ma       - (2)

From (1) & (2) :

m g = 5 m a a = g 5 = 2 m / s 2                

T = m g + m g 5 = 6 m g 5                     

New answer posted

12 months ago

0 Follower 11 Views

A
alok kumar singh

Contributor-Level 10

Sol. V?1=2Ucm?-U1?2m/2Vom2+m3-Vo

65Vo-VoV05

λo=hcm2Voλf=hcM2Vo5

Δλ=8hcmVo

New answer posted

12 months ago

0 Follower 5 Views

P
Payal Gupta

Contributor-Level 10

Using conservation of momentum:

60 * v = (60 + 120) * 2

⇒  v = 6m/s

New answer posted

12 months ago

0 Follower 5 Views

A
alok kumar singh

Contributor-Level 10

K=QrΔxΔAT

ML2T-2 (L)L2 (θ) (T)M1L1-T-3θ-1

New answer posted

12 months ago

0 Follower 4 Views

P
Payal Gupta

Contributor-Level 10

L=r*mv

(3i^j^)* (3j^+k^)

=9k^+3 (j^)i^

=i^3j^+9k^

|L|==√1+9+81==√91

New answer posted

12 months ago

0 Follower 5 Views

P
Payal Gupta

Contributor-Level 10

xR=120?

xL=? L=100*100*10? 310?

xC=1? c=1100*100*10? 6=100?

z=1202+ (100? 10)2=1202+902

= 150 ?

? 32=16075*t? t=32*75160=15

New answer posted

12 months ago

0 Follower 6 Views

A
alok kumar singh

Contributor-Level 10

eVs=hv-?

 At Vs=0hv=? ? =6.62*10-341014 [5.5]? =6.62*10-341014 [5.5]eV1.6*10-19

=2.27

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