Physics

Get insights from 5.6k questions on Physics, answered by students, alumni, and experts. You may also ask and answer any question you like about Physics

Follow Ask Question
5.6k

Questions

0

Discussions

24

Active Users

0

Followers

New answer posted

a year ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

 g=Axx2+a23/2

⇒∫v0?dV=-∫x∞?gdx

⇒O-V=-∫Axa2+x23/2

Let, a2+x2=t2

⇒2xdx=2tdt

⇒xdx=tdt

⇒V=∫Atdtt3⇒-At⇒-Aa2+x2x∞

⇒ V = A a 2 + x 2

New answer posted

a year ago

0 Follower 8 Views

A
alok kumar singh

Contributor-Level 10

ρvg-mg=ma

⇒ρvgm=g+a

⇒m=ρvgg+a

⇒10343π*10-6 (9.8)9.898

⇒4.15gm

New answer posted

a year ago

0 Follower 9 Views

A
alok kumar singh

Contributor-Level 10

(n) λ=5

(n, m) : Integers

2m+12λ=32⇒3/25=2m+12n⇒3n=10m+5

N, m are integers.

So,  m=1, n=5, λ=1

m=4n=15λ=13m=7n=25λ=15

New answer posted

a year ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution 

New answer posted

a year ago

0 Follower 9 Views

A
alok kumar singh

Contributor-Level 10

τ? =μ? *B?

⇒0.018=μ (0.06)sin? 30? ⇒μ=0.6⇒ Work =Uf-Ui⇒2μB⇒7.2*10-2J.

New answer posted

a year ago

0 Follower 5 Views

A
alok kumar singh

Contributor-Level 10

E= (I) (t) (A)cos2? θ
⇒ (3.3)2π31.43*10-4*12

⇒0.99*10-4

New answer posted

a year ago

0 Follower 6 Views

P
Payal Gupta

Contributor-Level 10

C = 10-6 f

f = 0.5 * 103 = 500

z = x R 2 + ( x L − x C ) 2                

for minimum impedance :

xL = xC

⇒ ω 2 = 1 L C

⇒ L = 1 π 2 = 1 1 0 * 1 0 0 0 = 1 0 0 m H                                

New answer posted

a year ago

0 Follower 7 Views

A
alok kumar singh

Contributor-Level 10

m (L)=m1S1 (ΔT)

⇒m3.4*105= (200) (4200) (25)

⇒m=61.7

New answer posted

a year ago

0 Follower 14 Views

P
Payal Gupta

Contributor-Level 10

 r=mvqB=2kmqB

= 2*5*103*1.6*10−19*24*1.66*10−271.6*10−19*12

= 9.975 * 102 cm

= 9.975 cm

New answer posted

a year ago

0 Follower 6 Views

A
alok kumar singh

Contributor-Level 10

BA=μ0Iθ4πR

⇒BABB=IAθARBIBθBRA

⇒23π2 (4)35π3 [2]

⇒65 .

Get authentic answers from experts, students and alumni that you won't find anywhere else

Sign Up on Shiksha

On Shiksha, get access to

  • 67k Colleges
  • 1.2k Exams
  • 718k Reviews
  • 1850k Answers

Share Your College Life Experience

×
×

This website uses Cookies and related technologies for the site to function correctly and securely, improve & personalise your browsing experience, analyse traffic, and support our marketing efforts and serve the Core Purpose. By continuing to browse the site, you agree to Privacy Policy and Cookie Policy.