Physics Thermodynamics

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New answer posted

5 months ago

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V
Vishal Baghel

Contributor-Level 10

3C (Graphite) + 4H2 (g) -> C3H8 (g)

Δ H f ( C 3 H 8 ) = [ 3 * Δ H c o m b ( C ) ] + [ 4 * Δ H c o m b ( H 2 ) ] [ Δ H c o m b ( C 3 H 8 ) ]        

= -10.3.7 kJ/mole

New answer posted

5 months ago

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V
Vishal Baghel

Contributor-Level 10

For adiabatic process – PVY = const

T 1 V 1 Y 1 = T 2 V 2 Y 1

T 2 T 1 = ( v 1 v 2 ) Y 1 = ( d 2 d 1 ) Y 1 = ( 3 2 ) ( 7 5 1 ) = ( 3 2 ) 2 / 5

= ( 2 ) 2 = 4

New answer posted

5 months ago

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Payal Gupta

Contributor-Level 10

Q1=20°Cwater100°steam

Q1=mcΔT+mL

=m [cΔT+L]

=31000=31*103cal

Q2=293373*31*103

= 2 4 . 3 5 * 1 0 3 c a l

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5 months ago

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Payal Gupta

Contributor-Level 10

 dTdt=k (TT0)

dT (TT0)=kdt

k=16ln (23) - (1)

Now dTdt=k (TT0)

t = 10.257

t2 = 6 + 10.257 = 16.257 minutes

16.25 and or 16

New answer posted

5 months ago

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P
Payal Gupta

Contributor-Level 10

Q=Δυ+wnCΔT=nCvΔT=nCΔT4=34nCΔT=nCvΔT

C=43Cv=43*32R=2R

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5 months ago

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P
Payal Gupta

Contributor-Level 10

Heating energy =14th energy of the hammer

=14*12mv2

=14*12*1.5*60*60

=15*6*604*2

= 675 J

ΔT=67542=16.07°C

New answer posted

5 months ago

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V
Vishal Baghel

Contributor-Level 10

0.25 = 1 - T 2 T 1

0.25 = 1 - ( 2 7 + 2 7 3 ) T 1 3 0 0 T 1 = 1 0 . 2 5

3 0 0 T 1 = 0 . 7 5

T 1 = 3 0 0 * 1 0 0 7 5

T1 = 400 k

Now, efficiency increases by 100%

η 2 = 1 0 0 % η 1 + η 1

= 2 η 1

= 0.25 * 2

= 0.50

0.50 = 1 - T 2 ' T 1

T 2 ' T 1 = 0 . 5 0

T 1 ' = 3 0 0 0 . 5

T 1 ' = 6 0 0 k

T 1 ' T 1 =  (600 – 400) = 200 k or 200° C

New answer posted

5 months ago

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A
alok kumar singh

Contributor-Level 10

Given                                                                           

QAB = +40J

QBC = 0J

QCA = -60J

WCA =?

WBC = -50J (on the gas)

UA = 1560J

1st Law on path A to B

WAB +   Δ U = Q

Þ 0 +    [ U B U A ] = 4 0

Þ UB = UA + 40

= 1560 + 40

UB = 1600 J

 1st Low on path B

...more

New answer posted

5 months ago

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Vidhi Jain

Contributor-Level 10

One of the most important Mechanical Engineering subjects is Thermodynamics, which deals with the concepts of heat energy and temperature, along with its conversion between different forms. You would come across a variety of books that will give you a basic understanding of the concept, but here are a few book suggestions for Mechanical Engineering freshers to grasp the basics of thermodynamics quickly

  • Basic and Applied Thermodynamics by P. K. Nag
  • Engineering Thermodynamics by S. K. Som & G. Biswas
  • The Laws of Thermodynamics: A Very Short Introduction by Peter Atkins

New answer posted

5 months ago

0 Follower 9 Views

A
Ambika Singh

Contributor-Level 6

In GATE XE (Engineering Sciences), Thermodynamics is one of the optional sections (XE-E), but admissions for M.Tech are usually branch-specific (like Mechanical, Thermal, Energy Engineering).

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