Structure of Atom

Given: h = 6.626 * 10^-34 Js,

c = 3 * 10⁸ m s^-1,

λ = 4000 pm = 4000 * 10^-12 m = 4 * 10^-9 m

Energy of photon (E) = hc / λ

= (6.626 * 10^-34 Js) x (3 * 10⁸ m s^-1) / (4 * 10^-9 m) = 4.969 x 10^-17 J

i.e. 4.969 x 10^-17 J is the energy of 1 photon

Therefore, 1 J is the energy of photons = 1 / (4.969 x 10^-17) = 2.012 x 10¹⁶ photons.

Wavelength, λ = (3 * 10⁸ ms^-1) / (5 * 10⁹ s^-1) = 6.0 x 10^-2 m

Frequency, ν = 1 / 2.0 * 10^-10 s = 5.0 x 10⁹ s^-1

Wavenumber, (? ) = 1 / (6.0 x 10^-2 m) = 16.66 m^-1

(i) Energy of photon (E) = hν, where h= Plank's const, ν= Frequency

h= 6.626 * 10^-34 J s ; ν = 3 * 10¹⁵ Hz = 3 * 10¹⁵ s^-1

∴ E = (6.626 * 10^-34 J s) * (3 * 10¹⁵ s^-1) = 1.986 * 10¹⁸ J

(ii) Energy of photon (E) = hν = hc/λ, where λ= wavelength

h = 6.626 * 10^-34 J s ; c = 3 * 10⁸ m s^-1  λ= 0.50 Å = 0.5 * 10^-10 m.

∴ E = (6.626 * 10^-34 J s) * (3 * 10⁸ ms^-1) / 0.5 * 10^-10 m = 3.98 x 10^-15 J.

Kindly go through the solution.

Hello,

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All the very best for all of this, and I hope this helps!

It's depends on college or university. Fee structure can be semester wise, yearly wise or one time fees payment for the full course. But mostly in India semester wise and Yearly wise fees are collected from the students. 

Students must check the official website of their respective University or college before applying.