Structure of Atom
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A certain orbital has n= 4 and m? = -3. The number of radial nodes in this orbital is _______ (Round off to the nearest integer).
A certain orbital has n= 4 and m? = -3. The number of radial nodes in this orbital is _______ (Round off to the nearest integer).
For n = 4, the possible values of l are 0, 1, 2, 3.
For l = 3, and m = -3.
Radial nodes = (n - l - 1) = (4 - 3 - 1) = 0
Ans = 0
Upvote 
The difference between the radii of 3rd and 4th orbits of Li²⁺ in ΔR₁. The difference between the radii of 3rd and 4th orbits of He⁺ is ΔR₂. Ratio ΔR₁: ΔR₂ is:
The difference between the radii of 3rd and 4th orbits of Li²⁺ in ΔR₁. The difference between the radii of 3rd and 4th orbits of He⁺ is ΔR₂. Ratio ΔR₁: ΔR₂ is:
ΔR? = (a? /3) (16 – 9)
ΔR? = (a? /2) (16 – 9)
∴ ΔR? /ΔR? = 2/3
Upvote The shortest wavelength of H atom in the Lyman series is λ₁. The longest wavelength in the Balmer Series of H⁺ is:
The shortest wavelength of H atom in the Lyman series is λ₁. The longest wavelength in the Balmer Series of H⁺ is:
For hydrogen atom :
For Lyman series n? = 1 & n? = ∞
1/λH = RH [1/1² - 1/∞²] So, λ = 1/RH
For He? ion Balmer series n? = 2 & n? = 3
1/λHe? = RH × Z² [1/n? ² - 1/n? ²]
1/λHe? = RH × 4 × [1/4 - 1/9] = RH × 4 × (5/36)
1/λHe? = (5/9)RH = (5/9) (1/λ)
(λHe? ) = (9/5)λ
Upvote The region in the electromagnetic spectrum where the Balmer series lines appear is:
The region in the electromagnetic spectrum where the Balmer series lines appear is:
Balmer series lies in the visible region.
Upvote Among the statements (I-IV), the correct ones are:
(I) Be has smaller atomic radius compared to <!-- [if gte msEquation 12]>
(II) Be has higher ionization enthalpy than Al.
(III) Charge/radius ratio of is greater than that of <!-- [if gte msEquation 12]>
(IV) Both Be and Al form mainly covalent compounds.
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Among the statements (I-IV), the correct ones are:
(I) Be has smaller atomic radius compared to <!-- [if gte msEquation 12]>
(II) Be has higher ionization enthalpy than Al.
(III) Charge/radius ratio of is greater than that of <!-- [if gte msEquation 12]>
(IV) Both Be and Al form mainly covalent compounds.
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Charge / radius ratio of and is same because of diagonal relationship. Remaining statements are correct.
Upvote The strengths of 5.6 volume hydrogen peroxide (of density ) in terms of mass percentage and molarity , respectively, are:
(Take molar mass of hydrogen peroxide as <!-- [if gte msEquation 12]>
The strengths of 5.6 volume hydrogen peroxide (of density ) in terms of mass percentage and molarity , respectively, are:
(Take molar mass of hydrogen peroxide as <!-- [if gte msEquation 12]>
For
Molarity
Molarity
Upvote The photoelectric current from Na (work function, w? = 2.3eV) is stopped by the output voltage of the cell
Pt(s)/H?(g, 1 bar) | HCl (aq., pH = 1)|AgCl(s)|Ag(s).
The pH of aq. HCl required to stop the photoelectric current from K(w? = 2.25 eV), all other conditions remaining the same, is × 10?² (to the nearest integer).
Given,
2.303(RT/F) = 0.06 V; E°(AgCl|Ag|Cl?) = 0.22 V
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The photoelectric current from Na (work function, w? = 2.3eV) is stopped by the output voltage of the cell
Pt(s)/H?(g, 1 bar) | HCl (aq., pH = 1)|AgCl(s)|Ag(s).
The pH of aq. HCl required to stop the photoelectric current from K(w? = 2.25 eV), all other conditions remaining the same, is × 10?² (to the nearest integer).
Given,
2.303(RT/F) = 0.06 V; E°(AgCl|Ag|Cl?) = 0.22 V
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