Structure of Atom
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New answer posted
a month agoContributor-Level 9
Matching Compounds to their Class:
o Antacid: Cimetidine
o Artificial Sweetener: Alitame
o Antifertility: Novestrol
o Tranquilizers: Valium
New question posted
a month agoNew answer posted
a month agoContributor-Level 10
For n = 4, the possible values of l are 0, 1, 2, 3.
For l = 3, and m = -3.
Radial nodes = (n - l - 1) = (4 - 3 - 1) = 0
Ans = 0
New answer posted
a month agoNew answer posted
a month agoContributor-Level 10
For hydrogen atom :
For Lyman series n? = 1 & n? = ∞
1/λH = RH [1/1² - 1/∞²] So, λ = 1/RH
For He? ion Balmer series n? = 2 & n? = 3
1/λHe? = RH * Z² [1/n? ² - 1/n? ²]
1/λHe? = RH * 4 * [1/4 - 1/9] = RH * 4 * (5/36)
1/λHe? = (5/9)RH = (5/9) (1/λ)
(λHe? ) = (9/5)λ
New answer posted
2 months agoContributor-Level 10
Charge / radius ratio of and is same because of diagonal relationship. Remaining statements are correct.
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