Structure of Atom

It talks about the atom. According to the Greek philosophers earlier, the atoms were the smallest part of matter that cannot be further divisible. Later, Dalton's atomic theory suggested that atom is the ultimate particle of matter. This theory was challenged later on by experiments done towards the

JJ Thomson, through the cathode ray tube experiment, discovered electrons. He passes the electricity from the tube and sees rays coming from the negative end. These are tiny negatively charged particles, he named them electrons.

JJ Thomson's model of the atom proposed that an atom is like a sphere (pudding) and electrons are spread around it like a plum or chocolate chips. Basically atom is overall neutral.

The structure of an atom reflects how the atom is made, which includes the nucleus at the centre where protons and neutrons are present, and electrons revolving around the nucleus.

Uncertainty in speed = 90   $\times \frac{5}{100}=4.5m/s=\Delta V$

  $\Delta x=\frac{h}{4\pi m\Delta V}=\frac{6.63\times 10^{-34}}{4\times 3.14\times 10^{-2}\times 4.5}=1.173\times 10^{-33}$            

For 2S, number of radial moles = $n-\mathcal{l}-1=2-0-1=1$ and ${\Psi }^2\left(r\right)$  will always be positive

$\therefore option\left(B\right)iscorrect?$ it has one radial node and it is positive.

Radius of Bohr’s orbit $R_n=0.529\stackrel{o}{A}\times \frac{n^2}{z}$  

Radius of Bohr’s orbit for hydrogen,   $R_n=0.529\stackrel{o}{A}\times n^2$

For third orbit (R₃) = $0.529\stackrel{o}{A}\times 9$ = r₃ and

Fourth orbit (R₄) = $0.59\stackrel{o}{A}\times 16=r_4$

$\therefore r_4=\frac{16r_3}{9}$  

Work function, ${?}_0=6.63\times 10^{-19}J$  

Threshold wavelength  ${\lambda }_0=?$  

Using ;                 ${?}_0=\frac{hc}{{\lambda }_0}$  

${\lambda }_0=\frac{hc}{{?}_0}$  

=300 × 10^-9 m = 300 nm

V =  $\frac{nRT}{P}=\frac{0.90\times 0.0821\times 300}{18\times 32}\times 760=29.21\cong 29$

For 2S, number of radial moles = $n-\mathcal{l}-1=2-0-1=1$ and ${\Psi }^2\left(r\right)$  will always be positive

$\therefore option\left(B\right)iscorrect?$ it has one radial node and it is positive.