Surface Chemistry

Gas + Solid? GS? H = -ve
Adsorbed gas
Adsorption of gas is an exothermic process. Increase in temperature reduces the extent of adsorption.
x/m = Kp¹/? (n > 1)

According to Hardy-Schulze Rule coagulation value $\alpha \frac{1}{\text{Coagulation Power}}$

(x/m) = k (p)¹/? (1)
64 (x/m) = k (2p)¹/? (2)
From equation (1) and (2)
64 = 2¹/?
2? = 2¹/?
1/n = 6
n = 1/6
⇒ n = 0.167
= 16.7 * 10? ²

[Diagram of a micelle formed by sodium stearate in oil]
Spherical micelles forms and hydrocarbon part are water repelling and attracted by oily part.

  Phase |            Medium |          Colloid Type |
| (1) Cheese |            liquid | solid |    Gel |
| (2) Pumice stone |  gas | solid |        Solid sol |
| (3) Hair cream |      liquid | liquid |    Emulsion |
| (4) Cloud | liquid |  gas | Aerosol |

PV = nRT

1 * V = $\frac{3.12}{32}*0.0821*300$

V = 2.4 litre

Vol of O₂ adsorbed per gm = 2.4 / 1.2 = 2 litre

Electrophilic addition of bromine to an alkene is anti-addition, in which cis-alkene gives two enantiomers and trans – alkene gives meso form

Here; trans-but-2-ene will give meso products

$FeC{l}_3\underset{}{\overset{hydrolysis}{\to }}Fe{\left(OH\right)}_3\downarrow \underset{Adsorption}{\overset{F{e}^{3+}}{\to }}Fe{\left(OH\right)}_3|F{e}^{3+}\left(colloidalparticle\right)$                                                                                               

Freundlich adsorption isotherm

  $\frac{x}{m}=k{p}^{1/n}$          

$log\frac{x}{m}=\frac{1}{n}logp+logk$           

Comparing with y = mx + C

so, slope of given graph is  $\frac{1}{n}$  whose value varies from 0 to 1.

Freundlich adsorption Isotherm

$\left(\frac{x}{m}\right)=k{\left(P\right)}^{\frac{1}{n}}$           

At moderate pressure ;  $\frac{x}{m}$ varies non-linearly with P.

So, $x=\frac{1}{n}$