Surface Chemistry

Viscosity of the hydrophilic sol is always higher than H₂O, because dispersed phase particle attracted by dispersion medium.

When AgNO₃ is added to Kl solution, precipitate of Agl is formed which adsorb I^- ion from

Dispersion medium to give negatively charged sol

$AgN{O}_3+Kl\to Agl\downarrow +KN{O}_3$

Agl/l^-- negatively charged sol.

Here, $\lambda =\frac{h}{\sqrt[]{2*m*eV}}=\frac{6.63*10^{-34}}{\sqrt[]{2*1.6*10^{-19}*40000*9.1*10^{-31}}}m$  

$\therefore \lambda =0.614*10^{-11}m$  

$\lambda =6.14*10^{-12}m$ [the nearest integer = 6]

Tyndall effect is the optical characteristics of light in which comparable particle size of colloids and bombarded light wavelength can produce this type of effect. For scattering effect of light in Tyndall effect refractive index of dispersed phase and dispersion medium should be greatly different.

$\left[Ag{\left(N{H}_3\right)}_2\right]\left[Ag{\left(CN\right)}_2\right]contains{\left[Ag{\left(N{H}_3\right)}_2\right]}^{+}and{\left[Ag{\left(CN\right)}_2\right]}^{-}$

 ln ${\left[Ag{\left(N{H}_3\right)}_2\right]}^{+},$  oxidation state of Ag = +1

$ln{\left[Ag{\left(CN\right)}_2\right]}^{-}$   , oxidation state Ag = +1

Hence; sum of oxidation state = 2

$\left(\frac{x}{m}\right)=K{P}^{1/n}$           

$\frac{10}{1}=K{\left(100\right)}^{1/n}................\left(1\right)$     

$\frac{15}{1}=K{\left(200\right)}^{1/n}................\left(2\right)$

$\frac{V}{1}=K{\left(300\right)}^{1/n}...............\left(3\right)$

Dividing (2) by (1)

$\frac{15}{10}={\left(\frac{2}{1}\right)}^{1/n}$ = (2)^1/n

$\frac{V}{10}=10^{0.279}$

$V=10*10^{0.279}=10^{1.279}=10^x$

$\therefore x=1.279=127.91*10^{-2}\approx 128*10^{-2}$

Ans. = 128

By increases in temperature absorption decreases, T₁ > T₂ means higher absorption at T₂ temperature.

In the lyophilic colloids, the colloidal particles are extremely solvated.

FeCl₃ + K₄ [Fe (CN)₆] (Potassium ferrocyanide)

excess

|

K Fe [Fe (CN)₆]

(colloidal species)

Prussian Blue coloured 

colloidal complex