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6 months ago

Surface Chemistry Class 12th

When 200mL of 0.2 M acetic acid is shaken with 0.6g of wood charcoal, the final concentration of acetic acid after adsorption is 0.1M. The mass of acetic acid adsorbed per gram of carbon is ______________ g.

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Payal Gupta

Contributor-Level 10

Number of moles of CH₃COOH Adsorbed on 0.6 gm wood charcoal.

$= (0.2 * 200) * 1 0^{- 3} - (0.1 * 200) * 1 0^{- 3}$

= 20 * 10^-3 moles

Mass of CH₃COOH absorbed = 20 * 10^-3 * 60 = 1.2 gm

Mass of CH₃COOH adsorbed per gram = $\frac{1.2}{0.6} = 2 g$ of charcoal.

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Surface Chemistry Class 12th

Given below are two statements :

Statement I : Emulsions of oil in water are unstable and sometimes they separate into two layers on standing.

Statement II : For stabilization of an emulsion, excess of electrolyte is added. In the light of the above statements, choose the most appropriate answer from the options given below :

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Vishal Baghel

Contributor-Level 10

Emulsions gets separated into two layers on standing.

For stabilization of emulsion. Emulsifying agents added into it but not electrolyte.

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Surface Chemistry Class 12th

Hydrogen has three isotopes : protium (¹H), deuterium (²H or D) and tritium (³H or T). They have nearly same chemical properties but different physical properties. They differ in

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alok kumar singh

Contributor-Level 10

Isotopes are the atom of same element with different atomic mass.

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Surface Chemistry Class 12th

Given below are two statements. One is labelled as Assertion A and the other is labelled as Reason R.

Assertion (A) : The first ionization enthalpy for oxygen is lower than that of nitrogen

Reason (R) : The four electrons in 2p orbitals of oxygen experience more electron electorn repulsion.

In the light of the above statements, choose the correct answer from the options given below:

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Vishal Baghel

Contributor-Level 10

1st ionization energy of N>O in oxygen atom, 2 electrons out of 4 electron of 2p orbital resulting in an increased electron repulsion.

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6 months ago

Surface Chemistry Chemistry NCERT Exemplar Solutions Class 12th Chapter Two

Which one of the following is an example of disproportionation reaction?

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Vishal Baghel

Contributor-Level 10

Disproportionation reaction is

$\overset{+ 6}{M g} O_{4}^{- -} + 4 H^{+} \to 2 \overset{+ 7}{M n} O_{4}^{-} + \overset{+ 4}{M n} O_{2} + 2 H_{2} O$

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6 months ago

Surface Chemistry Physics NCERT Exemplar Solutions Class 12th Chapter Five

Consider the ions /molecule $O_{2}^{+}, O_{2}, O_{2}^{-}, O_{2}^{2 -}$

For increasing bond order the correct option is

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Payal Gupta

Contributor-Level 10

$B o n d o r d e r = \frac{e^{-} o f B o n d i n g M O - e^{-} o f A B M O}{2}$

Hence Bond order for $O_{2}^{+} = \frac{10 - 5}{2} = 2.5$

$O_{2} = \frac{10 - 6}{2} = 2.0$

$O_{2}^{-} = \frac{10 - 7}{2} = 1.5$

$O_{2}^{- -} = \frac{10 - 8}{2} = 1.0$

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6 months ago

Surface Chemistry Chemistry NCERT Exemplar Solutions Class 12th Chapter Five

Which of the following is a correct statements?

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alok kumar singh

Contributor-Level 10

Due to equal and similar charge particle will repel each other, hence will never precipitate

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Surface Chemistry Chemistry NCERT Exemplar Solutions Class 12th Chapter Five

Which of the following is a correct statements?

(a) Brownian motion destabilizes sols

(b) Any amount of dispersed phase can be added to emulsion without establishing it.

(c) Mixing two oppositely charged sols in equal amount neutralizes charges and stabilizes colloids.

(d) Presence of equal and similar charges on colloidal particles provides stability to the colloidal solution.

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alok kumar singh

Contributor-Level 10

Due to equal and similar charge particle will repel each other, hence will never precipitate.

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Surface Chemistry Chemistry NCERT Exemplar Solutions Class 12th Chapter Five

Given below are two statements : one is labeled as Assertion A and the other is labeled as Reason R.

Assertion A: Finest gold is red in colour, as the size of the particles increase, it appears purple then blue and finally gold.

Reason R: The colour of the colloidal solution depends on the wavelength of light scattered by the dispersed particles.

In the light of the above statements, choose the most appropriate answer from the options given below.

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alok kumar singh

Contributor-Level 10

the finest gold sol is red in colour, as the size of particle increases, it appears purple then blue and finally gold. The colour of colloidal solution depends on the wavelength of light scattered by the dispersed particles. The wavelength of light further depends on size and nature of the particles. Hence, both assertion and reason are true and reason is the correct explanation of assertion.

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6 months ago

Surface Chemistry Chemistry NCERT Exemplar Solutions Class 12th Chapter Five

The nature of charge on resulting colloidal particles when FeCl₃ is added to excess of hot water is

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Payal Gupta

Contributor-Level 10

$F e C l_{3} \to_{}^{h y d r o l y s i s} F e {(O H)}_{3} ↓ \to_{A d s o r p t i o n}^{F e^{3 +}} F e {(O H)}_{3} | F e^{3 +} (c o l l o i d a l p a r t i c l e)$

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