Chemistry

Using $\lambda =\frac{h}{\sqrt[]{2qVm}}$  

${\lambda }_{Li}=\frac{h}{\sqrt[]{2*3e*V*8.3m}}$  m = mass of proton

${\lambda }_p=\frac{h}{\sqrt[]{2*e*V*m}}$  

$\frac{{\lambda }_{Li}}{{\lambda }_p}=\sqrt[]{\frac{2eVm}{2*24.9eVm}}$            

= 0.2 = 2 * 10^-1

So; x = 2

λ = h/p there is inverse relation between de-Broglie wavelength and momentum, hence the graph will be rectangular hyperbola.

Micelles are not formed because it formed above CMC.

W = 4.5 g

M.W = 90

V = 250 ml

Using M = $\frac{W}{M.W*V}*1000$  

$M=\frac{4.5}{90*250}*1000=0.2$       

M = 2 * 10^-1 M

So, x = 2

(A) SiO? has three-dimensional network structure of Si – O bonds; while carbon dioxide consists of discrete CO? molecules. SiO? is solid, whereas CO? is a gas
(B) Because of its great affinity for oxygen, Si always occurs as the oxide, silica (SiO? ) or in the form of silicates, which are the compounds of SiO? with other metal oxides.
(C) SiO? + 2Mg → Si + 2MgO
(D) The reluctance of silicon to form pπ – pπ bonds to itself is clearly shown by the fact that silicon does not exist in graphite-like structure, but only in diamond like structure.

Kindly consider the following Image 

The balanced equation is :

$S_8\left(s\right)+12O{H}^{-}\left(aq\right)\to 4S^{2-}\left(aq\right)+2S_2{O}_3^{2-}\left(aq\right)+6H_{2}O\left(\mathcal{l}\right)$           

Here ; a = 12

$\Delta T_f=0.5°C$

K_f = 1.86

Using, density of water = 1g / mL

i = ?

$\Delta T_f=i{k}_f.m$           

$0.5=i*1.86*\frac{9.45}{94.5*500}*1000$          

i = 1.344

Now, using $\alpha =\frac{i-1}{n-1}$  

n for ClCH₂COOH = 2

 a =   $\frac{1.344-1}{2-1}=0.344$

Using

  $K_a=\frac{C{\alpha }^2}{1-\alpha }$           

$K_a=\frac{0.2*{\left(0.344\right)}^3}{0.66}=36*10^{-3}$           

           So; x = 36

If the carbonyl compound is sterically crowded, then it will be reluctant to undergo addition reaction. Moreover, attachment of bulkier alkyl group with the carbonyl carbon decreases the partial positive charge resulting into the minimization of attack by R? from RMgBr. So, the order is