Chemistry

Molar mass of C₇H₅N₃O₆ = 12 * 7 + 1 * 5 + 14 * 3 + 16 * 6 = 84 + 42 + 96 = 227 g/mol

Number of moles =  $\frac{681}{227}$  = 3 mol

$\therefore$  number of N-atoms

$=3*6.02*10^{23}*3=9*6.02*10^{23}$  

$=5418*10^{21}$  

$\therefore x=5418$  

Alitame is an artificial sweetener. It is a second generation of dipeptide sweetener. It is 200 times sweeter than sucrose.

Using $\lambda =\frac{h}{\sqrt[]{2qVm}}$  

${\lambda }_{Li}=\frac{h}{\sqrt[]{2*3e*V*8.3m}}$  m = mass of proton

${\lambda }_p=\frac{h}{\sqrt[]{2*e*V*m}}$  

$\frac{{\lambda }_{Li}}{{\lambda }_p}=\sqrt[]{\frac{2eVm}{2*24.9eVm}}$            

= 0.2 = 2 * 10^-1

So; x = 2

λ = h/p there is inverse relation between de-Broglie wavelength and momentum, hence the graph will be rectangular hyperbola.

Micelles are not formed because it formed above CMC.

W = 4.5 g

M.W = 90

V = 250 ml

Using M = $\frac{W}{M.W*V}*1000$  

$M=\frac{4.5}{90*250}*1000=0.2$       

M = 2 * 10^-1 M

So, x = 2

(A) SiO? has three-dimensional network structure of Si – O bonds; while carbon dioxide consists of discrete CO? molecules. SiO? is solid, whereas CO? is a gas
(B) Because of its great affinity for oxygen, Si always occurs as the oxide, silica (SiO? ) or in the form of silicates, which are the compounds of SiO? with other metal oxides.
(C) SiO? + 2Mg → Si + 2MgO
(D) The reluctance of silicon to form pπ – pπ bonds to itself is clearly shown by the fact that silicon does not exist in graphite-like structure, but only in diamond like structure.

Kindly consider the following Image 

The balanced equation is :

$S_8\left(s\right)+12O{H}^{-}\left(aq\right)\to 4S^{2-}\left(aq\right)+2S_2{O}_3^{2-}\left(aq\right)+6H_{2}O\left(\mathcal{l}\right)$           

Here ; a = 12

$\Delta T_f=0.5°C$

K_f = 1.86

Using, density of water = 1g / mL

i = ?

$\Delta T_f=i{k}_f.m$           

$0.5=i*1.86*\frac{9.45}{94.5*500}*1000$          

i = 1.344

Now, using $\alpha =\frac{i-1}{n-1}$  

n for ClCH₂COOH = 2

 a =   $\frac{1.344-1}{2-1}=0.344$

Using

  $K_a=\frac{C{\alpha }^2}{1-\alpha }$           

$K_a=\frac{0.2*{\left(0.344\right)}^3}{0.66}=36*10^{-3}$           

           So; x = 36