Chemistry

When Ferric chloride reacts with potassium thiocyanate a blood red colour of Ferric thiocyanate is formed
FeCl? + 3KSCN → Fe (SCN)? + 3KCl

1000 ml solution contains 0.02 milli mole (mm)

$\therefore$ 500 ml solution contains 0.02 m.m

$\therefore$ Solution made 1000 ml with H₂O

$\therefore$ m.m in final solution = 0.01 mm

Solution (A) + 0.01 m. m H₂SO₄

= 0.01 + 0.01

= 0.02 m.m

                             = 0.00002 * 10³ mm

Formation of passive layer of Fe? O? on the surface of Fe and NO? gas is evolved
[Co (NH? )? ]³? is diamagnetic (t? g? eg? ) and is inner orbital complex

$\Delta H=-165kJ/mole$

T =?

$\Delta S=-550J{K}^{-1}$

At equilibrium $\Delta G=0$

$\therefore T=\frac{\Delta H}{\Delta S}=\frac{-165*1000}{-550}K$

$\begin{array}{l}=3*100K\\ =300K\end{array}$

i. Zn + 2NaOH → Na? ZnO? + H?
ii. 4Au + 8NaCN + O? + 2H? O → 4Na [Au (CN)? ]+ 4NaOH
iii. Cu + 4HNO? → Cu (NO? )? + 2NO? + 2H? O
(conc.)

K = 3.3 * 10^-4 s^-1

Time for 40% completion ; t

Using $K=\frac{2.303}{t}lo{g}_{10}\frac{{\left[R\right]}_0}{\left[R\right]}$  

3.3 * 10^-4 =   $\frac{2.303}{t}lo{g}_{10}\frac{{\left[R\right]}_0}{0.6{\left[R\right]}_0}$

  $t=\frac{2.303}{3.3}*10^4*0.22\Rightarrow t=25.58mins$            

so; the nearest integer is 26.

Coordination no. of an atom in BCC is 8.

To stop bleeding, FeCl? is applied locally because FeCl? causes denaturation of proteins present in blood. It is a case of coagulation.

$E_{1_H}=-2.2*10^{-18}J$

$Li\to L{i}^{+2}+2e^{-},n=2$

$E_{L{i}^{+2}}=E_{1H}*\frac{Z^2}{n^2}=-2.2*10^{-18}*\frac{3^2}{2^2}$

$\lambda =4*10^{-8}$ m

$d=\frac{ZM}{N_A{a}^3}=\frac{4*58.5}{6.02*10^{23}*a^3}$

$43.1=\frac{4*58.5}{6.02*10^{23}*a^3}$

$\therefore a=2.08*10^{-8}cm$

$\therefore r_{N{a}^{+}}+r_{C{l}^{-}}=1.04*10^{-10}$ m