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8 months ago

Chemistry Class 12th

If ${[C u {(H_{2} O)}_{4}]}^{2 +}$ absorbs a light of wavelength 600nm d-d transition, then the value of octahedral crystal field splitting energy for ${[C u {(H_{2} O)}_{6}]}^{2 +}$ will be_________* 10^-^21J. (Nearest Integer)

(Given: h = 6.63 * 10^-³⁴ Js and c = 3.08 * 10⁸ ms^-¹)

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Payal Gupta

Contributor-Level 10

$Δ_{t} = \frac{h c}{λ} = \frac{6.63 * 1 0^{- 34} * 3.08 * 1 0^{8}}{600 * 1 0^{- 9}}$

$= \frac{6.63 * 3.08 * 1 0^{- 17}}{600}$ J

$= 765.765 * 1 0^{- 21} J$

$? 766 * 1 0^{- 21}$ J

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8 months ago

Chemistry Class 12th

For a given chemical reaction

$γ_{1} A + γ_{2} B \to γ_{3} C + γ_{4} D$

Concentration of C charges form 10 mmol dm^-³ to 20 mmol dm^-³ in 10 second. Rate of appearance of D is 1.5 times the rate of disappearance of B which is twice the rate of disappearance A. The rate of appearance of D has been experimentally determined to be 9 mmol dm^-³ s^-¹. Therefore the rate of reaction is_____________mmol dm^-³ s^-¹ (Nearest Integer)

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Payal Gupta

Contributor-Level 10

$\frac{d [C]}{d t} = (\frac{20 - 10}{10}) = 1 m m o l d m^{- 3}$

$+ \frac{d [D]}{d t} = {- \frac{d (B)}{d t}} * 1.5 = \frac{3}{2} {- \frac{d [B]}{d t}}$

${- \frac{d [B]}{d t}} = 2 * {\frac{- d [A]}{d t}}$

$∴ \frac{1}{6} {\frac{- d [B]}{d t}} = \frac{1}{3} {\frac{- d [A]}{d t}} = \frac{1}{9} {\frac{+ d [D]}{d t}} = \frac{d [C]}{d t}$

$∴$ rate of reaction = $\frac{+ d [C]}{d t}$ = 1m.m dm^-3 S^-1

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8 months ago

Chemistry Chemistry Electrochemistry

In a cell, the following reactions take place

Fe²⁺ → Fe³⁺ $E_{F e^{3 +} / F e^{2 +}}^{0} = 0.77 V$

2I^- → I₂ + 2e^- $E_{I_{2} / I^{-}}^{0} = 0.54 V$

The standard electrode potential for the spontaneous reaction in the cell is x * 10^-² V 298 K. The value of x is________(Nearest Integer)

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Payal Gupta

Contributor-Level 10

$F e^{+ 3} + l^{-} \to I_{2} + F e^{+ 2}$

Fe⁺² undergoes reduction & I₂ undergoes oxidation.

$E_{c e l l}^{o} = E_{c a t h o d e}^{o} - E_{a n o d e}^{o}$

= (0.77 – 0.54) V = 0.23 V

= 23 * 10^-2 V

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8 months ago

Chemistry Class 11th

The standard free energy change $(Δ G °)$ for 50% dissociation of N₂O₄ into NO₂ at $27 ° C$ and 1 atm pressure is -xJ mol^-¹. The value of x is_________. (Nearest Integer)

[Given: R= 8.31 J k^-¹ mol^-¹, log 1.33 = 0.1239, In 10 = 2.3]

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Payal Gupta

Contributor-Level 10

$N_{2} O_{4} ? 2 N O_{2}$

$\underset{= 0.5 m o l}{(1 - 0.5)}$ $2 * 0.5 = 1 m o l$

$k_{P} = \frac{{(\frac{1}{1.5} * 1)}^{2}}{(\frac{0.5}{1.5} * 1)}$

$= \frac{4}{3} = 1.33$

$= - 710.15 J / m o l$

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8 months ago

Chemistry Chemistry Some Basic Concepts of Chemistry

1L aqueous solution of H₂SO₄ contains 0.02m mol H₂SO₄. 50% of this solution is dilutd with deionized water to give 1L solution (A). In solution (A), 0.01m mol of H₂SO₄ are added. Total m mols of H₂SO₄ in the final solution is ________* 10³ m mols

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Payal Gupta

Contributor-Level 10

1000 ml solution contains 0.02 milli mole (mm)

$∴$ 500 ml solution contains 0.02 m.m

$∴$ Solution made 1000 ml with H₂O

$∴$ m.m in final solution = 0.01 mm

Solution (A) + 0.01 m. m H₂SO₄

= 0.01 + 0.01

= 0.02 m.m

= 0.00002 * 10³ mm

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8 months ago

Chemistry Class 11th

The standard entropy change for the reaction $4 F e (s) + 3 O_{2} (g) \to 2 F e_{2} O_{3} (s) i s - 550 J K^{- 1} a t 298 K$

[Given: The standard enthalpy change for the reaction is -165 kJ mol^-¹]. The temperature in K at which the reaction attains equilibrium is__________.

[Nearest Integer)

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Payal Gupta

Contributor-Level 10

$Δ H = - 165 k J / m o l e$

T =?

$Δ S = - 550 J K^{- 1}$

At equilibrium ; $Δ G = 0$

$∴ T = \frac{Δ H}{Δ S} = \frac{- 165 * 1000}{- 550} K$

$\begin{array}{l} = 3 * 100 K \\ = 300 K \end{array}$

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8 months ago

Chemistry Structure of Atom

The longest wavelength of light that can be used for the ionization of lithium atom (Li) in its ground state is x * 10^-⁸m. The value of x is_________. (Nearest Integer)

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Payal Gupta

Contributor-Level 10

$E_{1_{H}} = - 2.2 * 1 0^{- 18} J$

$L i \to L i^{+ 2} + 2 e^{-}, n = 2$

$E_{L i^{+ 2}} = E_{1 H} * \frac{Z^{2}}{n^{2}} = - 2.2 * 1 0^{- 18} * \frac{3^{2}}{2^{2}}$

$λ = 4 * 1 0^{- 8}$ m

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8 months ago

Chemistry Class 11th

The number of N atoms in 681 g of C₇H₅N₃O₆ is x * 10²¹. The value of x is___________.

(N_A = 6.02 * 10²³ mol^-¹) (Nearest Integer)

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Payal Gupta

Contributor-Level 10

Molar mass of C₇H₅N₃O₆= 12 * 7 + 1 * 5 + 14 * 3 + 16 * 6 = 84 + 42 + 96 = 227 g/mol

Number of moles = $\frac{681}{227}$ = 3 mol

$∴$ number of N-atoms

$= 3 * 6.02 * 1 0^{23} * 3 = 9 * 6.02 * 1 0^{23}$

$= 5418 * 1 0^{21}$

$∴ x = 5418$

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8 months ago

Chemistry Class 11th

Phenol on reaction with dilute nitric acid, gives two products. Which method will be most efficient for large scale separation?

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Payal Gupta

Contributor-Level 10

Ortho product has intramolecular H- bonding & para product has intermolecular H- bonding. Thus it can be separated by steam distillation due to difference in B.

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8 months ago

Chemistry Class 11th

The eutrophication of water body results in

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Payal Gupta

Contributor-Level 10

Eutrophication of water body results in loss of biodiversity.

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