Chemistry

$4\mathrm{L}\mathrm{i}+{\mathrm{O}}_2?2{\mathrm{L}\mathrm{i}}_2\mathrm{O}\mathrm{}$ oxide

$2\mathrm{N}\mathrm{a}+{\mathrm{O}}_2?{\mathrm{N}\mathrm{a}}_2{\mathrm{O}}_2$ peroxide

$\mathrm{K}+{\mathrm{O}}_2?{\mathrm{K}\mathrm{O}}_2\mathrm{}$ superoxide

 $2Mn{O}_4+16HCl\to 2MnC{l}_2+2KCl+8H_{2}O+C{l}_2$

$KMn{O}_4$ oxidizes HCl to Cl₂, so HCl is not used in permanganate titration.

$\mathrm{U}$ and $\mathrm{H}$ are temperature dependent

${\mathrm{C}}_{\mathrm{P},\mathrm{m}}-{\mathrm{C}}_{\mathrm{V},\mathrm{m}}=\mathrm{R}$  (for 1 mole of ideal gas)

$\mathrm{d}\mathrm{U}={\mathrm{C}}_{\mathrm{V}}\mathrm{d}\mathrm{t}$

 No. of electron = 62 – 2 = 60

$68^{E{r}^{+3}}$ No. of electron = 68 – 3 = 65

$70^{Y{b}^{+2}}$ No. of electron = 70 – 2 = 68

$71^{Lu+3}$ No. of electron = 71 – 3 = 68

$65^{T{b}^{+4}}$ No. of electron = 65 – 4 = 61

$63^{E{u}^{+2}}$ No. of electron = 63 – 2 = 61

$65^{T{b}^{+2}}$ No. of electron = 65 – 2 = 63

$69^{T{m}^{+4}}$ No. of electron = 69 – 4 = 65

$I_2+10HN{O}_3\left(conc\right)\to 2Hl{O}_3+10N{O}_2+4H_{2}O$

(i) Foam - Froth (e)
(ii) Gel - Jellies (c)
(iii) Aerosol - smoke (a)
(iv) Emulsion - milk (f)

$I_2+10HN{O}_3\left(conc\right)\to 2Hl{O}_3+10N{O}_2+4H_{2}O$

Alloy of Li & Mg is used to make armour plates and not aircraft plates. Calcium plays important roles in neuro-muscular function, interneuronal transmission and cell membrane integrity.

In Clark's method lime water is used

$\begin{array}{l}Ca{\left(HC{O}_3\right)}_2+2Ca{\left(OH\right)}_2\to 2CaC{O}_3+2H_{2}O\\ Mg{\left(HC{O}_3\right)}_2+2Ca{\left(OH\right)}_2\to 2CaC{O}_3+Mg{\left(OH\right)}_2+2H_{2}O\end{array}$

 $\Delta G=\Delta H-T\Delta S$

$\therefore \Delta$ S increases then (Ve) value of $\Delta G$ increases and it is easy to reduce. Entropy of liquid is greater than solid. On melting, entropy increases and $\Delta G$ becomes more negative.