Class 11th

Get insights from 8k questions on Class 11th, answered by students, alumni, and experts. You may also ask and answer any question you like about Class 11th

Follow Ask Question
8k

Questions

0

Discussions

38

Active Users

0

Followers

New answer posted

3 months ago

0 Follower 4 Views

V
Vishal Baghel

Contributor-Level 10

P = kV3 Þ PV-3 = k Þ Polytropic Process with index m = -3

W = n R ( T 2 T 1 ) 1 m = n R ( 3 0 0 1 0 0 ) 1 ( 3 ) = 5 0 n R .

New answer posted

3 months ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

NaCN converted into HCN and Na2S converted into H2S

N a C N + H N O 3 N a N O 3 + H C N N a 2 S + 2 H N O 3 N a N O 3 + H 2 S

New answer posted

3 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

Assume the length of train be I and its acceleration be a.

v 2 = u 2 + 2 a l a l = v 2 u 2 2

Velocity when middle point crosses the post,

V m = u 2 + 2 a l 2 . = u 2 + v 2 u 2 2 = u 2 + v 2 2

New answer posted

3 months ago

0 Follower 1 View

P
Payal Gupta

Contributor-Level 10

Bond dissociation enthalpy is the energy required to break 1 mole of bond according to experimental data

Bond energy : Cl2 > Br2 > F2 > l2

New answer posted

3 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

T = 2 π r 3 G M e

T B T A = 2 π G M e ( r B 3 / 2 r A 3 / 2 ) = 2 * 3 . 1 4 6 . 6 7 * 1 0 1 1 * 6 * 1 0 2 4 [ ( 8 * 1 0 6 ) 3 2 ( 7 * 1 0 6 ) 3 2 ]

New answer posted

3 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

For first resonance,

l + 0 . 3 d = v 4 f

l + 0 . 3 * 6 = 3 3 6 * 1 0 0 4 * 5 0 4 l = 1 4 . 8 c m

New answer posted

3 months ago

0 Follower 11 Views

A
alok kumar singh

Contributor-Level 10

For 3S number of radial nodes are

= n l 1 = 3 0 1 = 2

          

New answer posted

3 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

T = 2 π l g

2 = 2 π 2 g

g = 2 π 2 m / s 2

New answer posted

3 months ago

0 Follower 3 Views

P
Payal Gupta

Contributor-Level 10

Ca (OH)2 ?  Ca+ + 2OH-

S                      S           2S

K s p = 4 S 3

            

New answer posted

3 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

At constant pressure,

d U = n C V d T = n . 5 2 R d T

d Q = n C P d T = n . 7 2 R d T

dW = nRdT

dU : dQ : dW = 5 : 7 : 2

Get authentic answers from experts, students and alumni that you won't find anywhere else

Sign Up on Shiksha

On Shiksha, get access to

  • 65k Colleges
  • 1.2k Exams
  • 679k Reviews
  • 1800k Answers

Share Your College Life Experience

×
×

This website uses Cookies and related technologies for the site to function correctly and securely, improve & personalise your browsing experience, analyse traffic, and support our marketing efforts and serve the Core Purpose. By continuing to browse the site, you agree to Privacy Policy and Cookie Policy.