Class 12th

Get insights from 11.9k questions on Class 12th, answered by students, alumni, and experts. You may also ask and answer any question you like about Class 12th

Follow Ask Question
11.9k

Questions

0

Discussions

49

Active Users

0

Followers

New answer posted

11 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

 f1=100=fo (CCVS)

C = Speed of sound

Vs = Speed of source

f2 = 50 = fo = (CC+Vs)

f1f2=2=C+VSCVS

fo=2003=x3

x = 200

New answer posted

11 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

R=R? A1/3

δ=massvolume=mA43πR3=mA4/3πR03A

 Density is independent of mass number

New answer posted

11 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

L = 1 m

ΔL=0.4*103m

m=1kg

d = 0.4 * 10-3 m

FA=yΔLL

y=FLAΔL= (mg)*1 (πd24)*0.4*103

Δy=0.1*0.199*1012=1.99*1010

= 1.99

New answer posted

11 months ago

0 Follower 3 Views

P
Payal Gupta

Contributor-Level 10

Siderite – FeCO3 (ore of iron)

Calamine – ZnCO3 (ore of zinc)

Malachite – CuCO3.Cu (OH)2 (ore of copper)

Cryolite – Na3AlF6 (ore of aluminium)

New answer posted

11 months ago

0 Follower 11 Views

A
alok kumar singh

Contributor-Level 10

 a1=m2gm1gm1+m2=2mgmg3m=g3

a2=3mgmg4m=g2

a1a2=23

New answer posted

11 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

Loss in P.E. = Gain in k.E

2 mg R = 12 (12mR2+mR2)ω2

ω=8g3R=4g2*3R

x=g2=5

New answer posted

11 months ago

0 Follower 11 Views

V
Vishal Baghel

Contributor-Level 10

y = x5 (1 - x) = x tanθ  (1xR)

tan = 5, R = 1

sinθ=526, cosθ=126

R=u2sin2θg=1

u2=26u=26m/s

y - component of initial velocity

= u sinθ 

=26*526

= 5 m/s

New answer posted

11 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

KE=728*1.6*1019=12*9.1*1031*V2

V = 16 * 106 m/s

For Lorentz force to be zero

eE = eVB

E=vB=16*106*12*103

= 192 * 103 V/m

New answer posted

11 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

 M=IA1IA2

M=7*227* [251009100]k^

M=72k^Am2

New answer posted

11 months ago

0 Follower 7 Views

A
alok kumar singh

Contributor-Level 10

I > When switch is closed

Ceq = 2C

Energy E1 = 12*Ceq*v2=12*2C*v2

E1 = CV2

II > When switch is opened

E2=12* (5c)*V2+ (Cv)22*5C

=135CV2

E1E2=513

Get authentic answers from experts, students and alumni that you won't find anywhere else

Sign Up on Shiksha

On Shiksha, get access to

  • 66k Colleges
  • 1.2k Exams
  • 703k Reviews
  • 1850k Answers

Share Your College Life Experience

×
×

This website uses Cookies and related technologies for the site to function correctly and securely, improve & personalise your browsing experience, analyse traffic, and support our marketing efforts and serve the Core Purpose. By continuing to browse the site, you agree to Privacy Policy and Cookie Policy.