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New answer posted

6 months ago

0 Follower 31 Views

V
Vishal Baghel

Contributor-Level 10

 2NO (g)+O2 (g)? 2NO2 (g)

Initial moles2mol1 mol

At equilibrium (2 – 2x) mole (1 – x) mol2x mol

no2 (1x)=0.6

x=0.4

nNO=22x=22*0.4

= 2 0.8 = 1.2

nNO2=2x=2*0.4=0.8

Kp= (0.82.6)2 (1.22.6)2 (0.62.6)

= 1.925

the nearest integer = 2.

New answer posted

6 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

 x2-3x+p=0

α, β, γ, δ in G.P.

α+αr=3

x2-6x+q=0

αr2+αr3=6

(2)÷ (1)r2=2

So,  2q+p2q-p=2r5+r2r5-r=2r4+12r4-1=97

New answer posted

6 months ago

0 Follower 6 Views

V
Vishal Baghel

Contributor-Level 10

 PT=PA+PB=0.8? ? atm

PA=PB=0.4atm

YA=0.5YB=0.5

XA=0.2

PAo=2atm.

New answer posted

6 months ago

0 Follower 1 View

M
Manori Pathak

Contributor-Level 7

Candidates seeking admission to various programmes can enrol for admission with Class 12/ graduation/ PG marks as per the course requirement. The college offers various UG courses in various streams such as Management Studies, Computer Science, etc. ISBMA, Chandigarh admissions are based on merit.

New answer posted

6 months ago

0 Follower 5 Views

V
Vishal Baghel

Contributor-Level 10

 λ=h2mEE=KineticEnergy

E=h22mλ2

= (6.626*1034)22*9.1*1031* (3.3*1010)2

= 2.215 * 10-18

Eabsorbed – Erequired + K. E

EabsorbedErequired=1+K.EErequired

=1+2.215*101813.6*1.602*1019=2.016

 2

New answer posted

6 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

 a=4*108cmz (F.C.C)=4

d = 9.03 g /ml

M=d*a3*NAZ

=9.03* (4*108)3*6.02*10234

=86.9787

New answer posted

6 months ago

0 Follower 17 Views

V
Vishal Baghel

Contributor-Level 10

H2SO4    +  2NaOH -> Na2SO4 + 2H2O             

Number of mole = 0.2 * 2                 2 * 0.1                 -              -

0.4 = 0.2

No. of moles after reaction =      0.4 – 0.1             0.2 – 0.2       &nbs

...more

New answer posted

6 months ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

eq of H2O2= eq of KMnO4

=0.316158*5=0.01=0.01*170.2*100=85%

New answer posted

6 months ago

0 Follower 9 Views

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

New answer posted

6 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

N2+3H2? 2NH3

2.8*103281*10320.1*103molLR0.5*103mol

 Mass of NH3 produced =0.2*103*17=3.4kg=3400g

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