Class 12th

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New answer posted

a year ago

0 Follower 5 Views

A
alok kumar singh

Contributor-Level 10

(a+2bcos?x)(a-2bcos?y)=a2-b2

⇒a2-2abcos?y+2abcos?x-2b2cos?xcos?y=a2-b2

Differentiating both sides:

0-2ab-sin?ydydx+2ab(-sin?x)-2b2cos?x-sin?ydydx+cos?y(-sin?x)=0

At π4,π4 :

abdydx-ab-2b2-12dydx-12=0⇒dxdy=ab+b2ab-b2=a+ba-b;a,b>0

New answer posted

a year ago

0 Follower 8 Views

A
alok kumar singh

Contributor-Level 10

f(x)=a?⋅(b?*c?)=x-23-2x-17-2x

=x3-27x+26

f'(x)=3x2-27=0⇒x=±3 and f''(-3)<0

⇒ local maxima at x=x0=-3

Thus, a?=-3iˆ-2jˆ+3kˆ,b?=2iˆ-3jˆ-kˆ , and c?=7iˆ-2jˆ-3kˆ

⇒a?⋅b?+b?⋅c?+c?⋅a?=9-5-26=-22

New answer posted

a year ago

0 Follower 5 Views

A
alok kumar singh

Contributor-Level 10

x‾=10

⇒x? =63+a+b8=10

⇒a+b=17

Since, variance is independent of origin.

So, we subtract 10 from each observation.

So,  σ2=13.5=79+ (a-10)2+ (b-10)28

⇒a2+b2-20 (a+b)=-171

⇒a2+b2=169

From (1) and (2) ; a=12 and b=5

New answer posted

a year ago

0 Follower 15 Views

A
alok kumar singh

Contributor-Level 10

 x2a2+y2b2=1(ab);2b2a=10⇒b2=5a

Now, ?(t)=512+t-t2=812-t-122
?(t)max=812=23=e⇒e2=1-b2a2=49

⇒a2=81 (From (i) and (ii)

So, a2+b2=81+45=126

New answer posted

a year ago

0 Follower 1 View

V
Vishal Baghel

Contributor-Level 10

State functions are

(a) Internal energy

(b) Volume

(c) Enthalpy

New answer posted

a year ago

0 Follower 5 Views

V
Vishal Baghel

Contributor-Level 10

 k=Ae−Ea/RT

lnk=lnA−EaRT

Comparing with y = mx + c

Slope = +EaR=+205

∴Ea=205R=4R=4*2cal

= 8 Cal

New answer posted

a year ago

0 Follower 11 Views

A
alok kumar singh

Contributor-Level 10

 f (2)=8, f' (2)=5, f' (x)≥1, f'' (x)≥4, ∀x∈ (1,6)

Using LMVT

f'' (x)=f' (5)-f' (2)5-2≥4⇒f' (5)≥17

f' (x)=f (5)-f (2)5-2≥1⇒f (5)≥11

Therefore f' (5)+f (5)≥28

New answer posted

a year ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

 IO4−+H2O2→IO3−+O2

Oxidation number of l in,  IO4−⇒x+ (−2)*4=−1∴x=+7

Oxidation number of in,  IO3−⇒x+ (−2)*3=−1∴x=+5

New answer posted

a year ago

0 Follower 10 Views

V
Vishal Baghel

Contributor-Level 10

 VN2=22.78mlT=280K

PTotal = 759 mm of Hg

PN2=759−14.2=744.8  mm  Hg

nN2=744.8* (22.78/1000) (0.082*760)*280

= 0.00097

%N=0.027160.125*100=21.728

≈22.

New answer posted

a year ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

∫03? g (x)-f (x)=∫03? ||x-2|-2|dx-∫03? |x-2|dx

=12*2*2+1+12*1*1-12*2*2+12*1*1

=2+1+12-2+12=1

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