Class 12th

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New answer posted

11 months ago

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A
alok kumar singh

Contributor-Level 10

Kindly go through the solution 

New answer posted

11 months ago

0 Follower 9 Views

A
alok kumar singh

Contributor-Level 10

τ? =μ? *B?

0.018=μ (0.06)sin? 30? μ=0.6 Work =Uf-Ui2μB7.2*10-2J.

New answer posted

11 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

E= (I) (t) (A)cos2? θ
(3.3)2π31.43*10-4*12

0.99*10-4

New answer posted

11 months ago

0 Follower 25 Views

V
Vishal Baghel

Contributor-Level 10

(x1)2+(y3)2=10α

xy=1x+y=a+b}m(a+b12,a+b+12)

A' = 2m – A = (b – 1, a + 1)

C2:x2+y2+2gx+2fy+385=0

g 2 + f 2 c

= 4 + 4 3 8 5 = 2 5

C 1 : 2 5 = 1 + 9 α = 1 0 α

α + 6 r 2 = 4 8 5 + 6 ( 2 5 ) = 6 0 5 = 1 2

New answer posted

11 months ago

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P
Payal Gupta

Contributor-Level 10

C = 10-6 f

f = 0.5 * 103 = 500

z = x R 2 + ( x L x C ) 2                

for minimum impedance :

xL = xC

ω 2 = 1 L C

L = 1 π 2 = 1 1 0 * 1 0 0 0 = 1 0 0 m H                                

New answer posted

11 months ago

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A
alok kumar singh

Contributor-Level 10

m (L)=m1S1 (ΔT)

m3.4*105= (200) (4200) (25)

m=61.7

New answer posted

11 months ago

0 Follower 49 Views

V
Vishal Baghel

Contributor-Level 10

T = {9, 10, 11, 12, …., 1000}

S = {4, 6, 9}

A =  {a1+a2+....+ak:kN, aiS}

Let 4 appear x no. of times

6 appear y no. of times

9 appear z no. of times

10 then set A has n element 4x + 6y + 9z

Concept : Let a and b are co-prime numbers, then members from (a - ) (b – 1) and more can be expressed in the form ax + by where x, y   {0, 1, 2, …}

So, all the number of the form

2y + 3z are (2 1). (3 – 1), ….

i.e., 6, 7, 8, 9, 10, 11, ….

form : 2 + t, t = 0, 1, 2, 3, ….

So, 6y + 9z = 3 (2y + 3z) = 3 (2 + t) = 6 + 3t, t = 0, 1, 2, 3, …

sum of element of T – A is 11

New answer posted

11 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

 tn=1 (n+1) (n+2) (n+3), n=1, 2, 3, ...., 99

=12 (1 (n+1) (n+2)1 (n+2) (n+3))=VnVn+1

=112 (1716101*17)=143101*17=k101k=14317

34 k = 286

New answer posted

11 months ago

0 Follower 14 Views

P
Payal Gupta

Contributor-Level 10

 r=mvqB=2kmqB

2*5*103*1.6*1019*24*1.66*10271.6*1019*12

= 9.975 * 102 cm

= 9.975 cm

New answer posted

11 months ago

0 Follower 12 Views

V
Vishal Baghel

Contributor-Level 10

Δ=p!(p+1)!(p+2)!Δ1=2p!(p+1);(p+2)!=2(p!)3.(p+1)2.(p+2)1α+β=3+1=4

Δ1=|1p+1(p+2)(p+1)1p+2(p+3)(p+2)1p+3(p+4)(p+3)|=|01(p+2)(2)01(p+3)(2)1p+3(p+4)(p+3)|

= 2(p + 3) – 2 (p + 2) = 2

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