Haloalkanes and Haloarenes

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Alcohols produce matching alkyl halides when they are treated with various reagents. Alcohols, red phosphorous, and bromine treated with alcohol produce alkyl chlorides and alkyl bromide, respectively, when treated with HCl+ZnCl₂. H₂SO₄ + KI cannot be used to convert an alcohol to alkyl iodide because they will convert KI to the equivalent acid, HI, which will then be oxidised to I₂. As a result, the right statements are (i) and (ii).

Correct Answer: Option (i) and (ii)

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Aryl halides are halides in which the halogen atom is directly linked to the aromatic ring's sp² hybridised carbon atom. Only (i) and (iv) contain halogen atoms directly linked to aryl rings among the choices. As a result, they are known as aryl halides. (i) and (ii) are the right answers (iv).

Correct Answer: Option (i) and (iv)

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Checking with the carbon atom it is connected to is one way to see if a compound has a secondary bromide. In a molecule, a secondary carbon group is linked to one hydrogen atom and three non-hydrogen groups. As a result of the foregoing possibilities, secondary bromides are formed when the -Br group is linked to the -CH group. (i) and (iii) are the right answers.

Correct Answer: Option (i) and (iii)

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Dihaloalkanes with two halogen atoms linked to the same carbon atom are known as gem-dihalides. Alkylidene halides are another name for them. The chemical ethylene dichloride is a vicinal dihalide, meaning that chlorine atoms are linked to neighbouring carbon atoms. There is only one chlorine atom in benzoyl chloride. According to the molecule's nomenclature, ethylidene chloride is a gem-dihalide. The IUPAC terminology for methylene chloride is dichloromethane. Two chlorine atoms are joined to a single carbon atom in this compound.

Correct Answer: Option (i) and (iii)

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Option (i) and (iv) have a halogen atom linked to an sp³ hybridised carbon that is single-bonded to other groups. The other possibilities are sp² hybridised because they are linked to carbon atoms, which are coupled to other groups in double bonds. Option I and (iv) are both correct.

Correct Answer: Option (i) and (iv)

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The reaction is of the type S_N¹ nucleophilic substitution. This sort of reaction is governed by second order kinetics, in which the rate of reaction is determined only by the concentration of the reactant. A reaction's molecularity is defined as the number of molecules involved in the rate-determining phase. Because of second order kinetics, the moleculeity of this reaction is one. (i) and (iii) are the right answers .

Correct Answer: Option (A) and (C) 

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Because it is a tertiary alkyl halide, the described reaction is a nucleophilic substitution that follows the S_N¹ mechanism. It's a two-step process. The first step is the gradual breaking of a polarised C-Br bond, which results in the formation of a carbocation and a bromide ion. To complete the substitution, the stable intermediate carbocation is attacked by the nucleophile OH⁻. (i) and (iv) are the right statements.

Correct Answer: option (A) and (iv)

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Because the carbon atom is transiently linked to five atoms, the intermediate (iii) is less stable than reactant (ii), which is coupled to four groups.

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An S_N² reaction, also known as a nucleophilic substitution, is the reaction in question. The entering nucleophile causes the groups surrounding the carbon atom to migrate in the opposite direction of the nucleophile, causing the configuration of alkyl halides to invert. As a result, (b) and (d) will be in the opposite order. This reaction is also S_N² since there is just one phase in which OH^- is added and Cl^-  is removed at the same time. (i) and (ii) are the right answers.

Correct Answer: Option (A) and (B)