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New answer posted

a year ago

0 Follower 14 Views

V
Vishal Baghel

Contributor-Level 10

 A3*3, B3*3&AB=0

≠0≠0⇒|A|=0  &|B|=0 only .

New answer posted

a year ago

0 Follower 10 Views

V
Vishal Baghel

Contributor-Level 10

 z5+ (z¯)5

= (2+3i)5+ (2−3i)5

=2 (32−720+810)=244

New answer posted

a year ago

0 Follower 13 Views

V
Vishal Baghel

Contributor-Level 10

R = { (a, b): b = pq, where p, q ≥3 are prime}

⇒60*11=660

p, q ∈  {3, 5, 7, 11, 13, 17, 19, 23, 29, 3, 37, 41, 43, 47, 53, 59} total 16

p, q ∈  {3, 5, 7, 11, 13, 17, 19}

{3, 5, 7, 11, 13, 17, 19}

7 + 3 + 1 = 11

New answer posted

a year ago

0 Follower 5 Views

A
alok kumar singh

Contributor-Level 10

We have,  1-  (probability of all shots result in failure)  > 1 4

⇒ 1 - 9 10 n > 1 4 ⇒ 3 4 > 9 10 n ⇒ n ≥ 3

New answer posted

a year ago

0 Follower 5 Views

A
alok kumar singh

Contributor-Level 10

 Since,  limx→0? f (x)x exist ⇒f (0)=0

Now,  f' (x)=limh→0? f (x+h)-f (x)h=limh→0? f (h)+xh2+x2hh ( take y=h)

=limh→0? f (h)h+limh→.0? (xh)+x2

⇒f' (x)=1+0+x2

⇒f' (3)=10

New answer posted

a year ago

0 Follower 8 Views

A
alok kumar singh

Contributor-Level 10

D=1-232111-7a=0⇒a=8

also,  D1=9-23b1124-78=0⇒b=3

hence,  a-b=8-3=5

New answer posted

a year ago

0 Follower 5 Views

A
alok kumar singh

Contributor-Level 10

D1=-74-181515b6=0⇒b=-3D=14-1315ab6=0⇒21a-8b-66=0P:2x-3y+6z=15

so required distance =217=3

New answer posted

a year ago

0 Follower 9 Views

A
alok kumar singh

Contributor-Level 10

Given 2x2+3x+410=∑r=020?arxr

replace x by 2x in above identity :-

2102x2+3x+410x20=∑r=020??ar2rxr⇒210∑r=020??arxr=∑r=020??ar2rx(20-r)( from (i))

now, comparing coefficient of x7 from both sides

(take r=7 in L.H.S. and r=13 in R.H.S.)

210a7=a13213⇒a7a13=23=8

New answer posted

a year ago

0 Follower 6 Views

A
alok kumar singh

Contributor-Level 10

xdydx-y=x2(xcos?x+sin?x),x>0

dydx-yx=x(xcos?x+sin?x)⇒dydx+Py=Q

So, I.F. =e∫-1xdx1|x|=1x(x>0)

Thus, yx=∫1x(x(xcos?x+sin?x))dx

⇒yx=xsin?x+C

?y(π)=π⇒C=1

So, y=x2sin?x+x⇒(y)π/2=π24+π2

Also, dydx=x2cos?x+2xsin?x+1

⇒d2ydx2=-x2sin?x+4xcos?x+2sin?x

New answer posted

a year ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

 max {n (A), n (B)}≤n (A∪B)≤n (U)

⇒76≤76+63-x≤100

⇒-63≤-x≤-39

⇒63≥x≥39

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