Ncert Solutions Chemistry Class 11th

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New answer posted•a year ago
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a year ago

This is a Short Answer Type Questions as classified in NCERT Exemplar

Ans: In the first figure given above, the area which is under + overlapping is equal to the area under +- overlap. Both the overlaps cancel out with each other as they are oppositely charged. Due to cancelling out of the overlaps t

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New answer posted•a year ago
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a year ago

This is a Short Answer Type Questions as classified in NCERT Exemplar

Ans: (a) Which of the two compounds will have intermolecular hydrogen bonding and which compound is expected to show intramolecular hydrogen bonding.

Ans: The intramolecular hydrogen bonding is shown by compound (I) and the intermol

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New answer posted•a year ago
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a year ago

This is a Short Answer Type Questions as classified in NCERT Exemplar

Ans: In BrF5 the central bromine atom has 7 valence electrons. It makes five bonds with the fluorine atom and one lone pair of electron is left. Due to the lone pair-bond pair repulsions, BrF5 makes a structure of square pyramidal

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New answer posted•a year ago
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a year ago

This is a Short Answer Type Questions as classified in NCERT Exemplar

Ans: The electronic configurations of O2+ and O2 - according to molecular orbital theory is:

O2+: σ1s2 σ∗1s2 σ2s2 σ∗2s2 s2pz2, π2p2y , π2p2x, π*2p1x

O2- : σ1s2 σ∗1s2 σ2s2 σ∗2s2 s2pz2, π2p2y , π2p2x, π*2p2y π*2p1x

 

The bond order

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New answer posted•a year ago
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a year ago

This is a Short Answer Type Questions as classified in NCERT Exemplar

Ans: In the Lewis structure of PCl3, the phosphorus atom is surrounded by three bond pairs (chlorine atoms) and one lone pair. These four electron pairs are arranged in a tetrahedral geometry around the central phosphorus atom. Due

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New answer posted•a year ago
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a year ago

This is a Long Answer Type Questions as classified in NCERT Exemplar

Ans: Option (iii)

Molecules from hydrogen to nitrogen shows this type of electronic configuration:

σ1s < σ*1s< σ2s < σ*2s< [ π2px = π2py] < σ2pz< [ π*2px = π*2py] σ*2pz  in which σ2pz is filled after π2px and π2py

So, amongst the given elements only nitrogen will

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New answer posted•a year ago
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a year ago

This is a Long Answer Type Questions as classified in NCERT Exemplar

Ans: Option (ii)

(i) The electronic configuration of O2 is:

σ1s2 σ∗1s2 σ2s2 σ∗2s2 s2pz2 π2p2y π2p2x π*2p1y π*2p1x

Bond order = 1 2 ( Nb- Na)

Bond order = 1 2 (10-6)=2.0

The electronic configuration of N2 :

σ1s2 σ*1s2 σ2s2 σ*2s2 π2p2x, π2p2y σ2p

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New answer posted•a year ago
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a year ago

This is a Long Answer Type Questions as classified in NCERT Exemplar

Ans: Option (ii)

Nodal plane is a plane which passes through the nucleus and the probability of finding an electron on a nodal plane is zero. Amongst the above given molecular orbital, only π*2px  contains two nodal planes. Rest

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New answer posted•a year ago

Comprehension given below is followed by some multiple choice questions. Each question has one correct option. Choose the correct option.

Molecular orbitals are formed by the overlap of atomic orbitals. Two atomic orbitals combine to form two molecular orbitals called bonding molecular orbital (BMO) and anti bonding molecular orbital (ABMO). Energy of anti bonding orbital is raised above the parent atomic orbitals that have combined and the energy of the bonding orbital is lowered than the parent atomic orbitals. Energies of various molecular orbitals for elements hydrogen to nitrogen increase in the order :

σ1s < σ*1s< σ2s < σ*2s< [ π2px = π2py] < σ2pz< [ π*2px = π*2py] σ*2pz

for oxygen and fluorine order of energy of molecular orbitals is given below :

σ1s < σ*1s< σ2s < σ*2s< σ2pz< [ π2px = π2py] < [ π*2px = π*2py] σ*2pz

Different atomic orbitals of one atom combine with those atomic orbitals of the second atom which have comparable energies and proper orientation. Further, if the overlapping is head on, the molecular orbital is called ‘Sigma’, (σ) and if the overlap is lateral, the molecular orbital is called ‘pi’, (π). The molecular orbitals are filled with electrons according to the same rules as followed for filling of atomic orbitals. However, the order for filling is not the same for all molecules or their ions. Bond order is one of the most important parameters to compare the strength of bonds.

Which of the following statements is correct? 

(i) In the formation of dioxygen from oxygen atoms 10 molecular orbitals will be formed.

(ii) All the molecular orbitals in the dioxygen will be completely filled.

(iii) Total number of bonding molecular orbitals will not be same as total number of anti bonding orbitals in dioxygen. (iv) Number of filled bonding orbitals will be same as number of filled anti bonding orbitals.

10 Views|Posted a year ago
Asked by Vishal Baghel
S
a year ago

This is a Long Answer Type Questions as classified in NCERT Exemplar

Ans: (i) The electronic configuration of dioxygen is:

σ1s2 σ∗1s2 σ2s2 σ∗2s2 s2pz2 π2p2y π2p2x π*2p1y π*2p1x

(ii) As it can be seen from the electronic configuration of oxygen atom π*2p1X π*2p1Y  the are partially. So, the statem

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New answer posted•a year ago
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a year ago

This is a Long Answer Type Questions as classified in NCERT Exemplar

Ans: (i) Different types of hybridization in a carbon atom are:

(a) sp hybridization: The carbon atoms forming triple bonds with each other determines hybridized carbon. ( Cº C ).

(b) sp2 hybridization: The carbon atoms forming dou

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