Ncert Solutions Chemistry Class 11th
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The pressure of a moist gas at <!-- [if gte mso 9]><xml>
</xml><![endif]--> is 0.04 atm. The volume of the container is doubled at the same temperature. The new pressure of the moist gas is _______ × 10-1atm. (Nearest integer)
(Given: The vapour pressure of water at <!-- [if gte mso 9]><xml>
</xml><![endif]--> is 0.4 atm)
The pressure of a moist gas at <!-- [if gte mso 9]><xml>
(Given: The vapour pressure of water at <!-- [if gte mso 9]><xml>
Pressure of gas = pressure of moist gas – Vapour pressure of water
= 4 atm – 0.4 atm
= 3.6 atm
On doubling the volume, pressure of gas is halved :
Total pressure =
When 600 mL of 0.2 M HNO3 is mixed with 400 mL of 0.1 M NaOH solution in a flask, the rise in temperature of the flask is_________ × 10-2 °C.
(Enthalpy of neutralization = 57 kJ mol-1 and Specific heat of water = 4.2 JK-1 g-1)
(Neglect heat capacity of flask)
When 600 mL of 0.2 M HNO3 is mixed with 400 mL of 0.1 M NaOH solution in a flask, the rise in temperature of the flask is_________ × 10-2 °C.
(Enthalpy of neutralization = 57 kJ mol-1 and Specific heat of water = 4.2 JK-1 g-1)
(Neglect heat capacity of flask)
What is the name of the second chapter of Class 11 chemistry?
Chapter 2 is Structure of Atom, aka the OG Science breakdown of how literally everything exists. You'll learn stuff like Bohr's model, orbitals, quantum numbers — all the nerdy magic that makes atoms behave. Sounds heavy, but once you get the hang of it, it lowkey feels like unlocking the Matrix. Tr
What is the use of Class 11 Chemistry Chapter 9 Hydrocarbons NCERT Solutions?
NCERT solutions for class 11 Chemistry chapter 9 hydrocarbon are crucial for understanding the fundamental principle of organic chemistry including the classification nomenclature and reaction of alkanes and alkyne and their vital role in daily life as fuse and in the manufacturing of polymer and ot
Ka for butyric acid (C3H7COOH) is 2 × 10-5. The pH of 0.2 M solution of butyric acid is ____________× 10-1 (Nearest integer)
[Given log2 = 0.30]
Ka for butyric acid (C3H7COOH) is 2 × 10-5. The pH of 0.2 M solution of butyric acid is ____________× 10-1 (Nearest integer)
[Given log2 = 0.30]
Ka for C3H7COOH = 2 × 10-5
=5 – 0.3 = 4.7
pH of 0.2 (M) solution =
Ans 27
The standard free energy change <!-- [if gte mso 9]><xml>
</xml><![endif]--> for 50% dissociation of N2O4 into NO2 at <!-- [if gte mso 9]><xml>
</xml><![endif]--> and 1 atm pressure is -xJ mol-1. The value of x is_________. (Nearest Integer)
[Given: R= 8.31 J k-1 mol-1, log 1.33 = 0.1239, In 10 = 2.3]
The standard free energy change <!-- [if gte mso 9]><xml>
[Given: R= 8.31 J k-1 mol-1, log 1.33 = 0.1239, In 10 = 2.3]
The standard entropy change for the reaction <!-- [if gte mso 9]><xml>
</xml><![endif]-->
[Given: The standard enthalpy change for the reaction is -165 kJ mol-1]. The temperature in K at which the reaction attains equilibrium is__________.
[Nearest Integer)
The standard entropy change for the reaction <!-- [if gte mso 9]><xml>
[Given: The standard enthalpy change for the reaction is -165 kJ mol-1]. The temperature in K at which the reaction attains equilibrium is__________.
[Nearest Integer)
Where can I get NCERT Class 11 Chemistry Chapter 11 exercise Solutions?
Here are some of the best NCERT Class 11 Chemistry Chapter 11 exercise solutions you can download and study .
1. LearnCBSE
Provides detailed, step by step solutions covering every question—from Intext to Exercise problems.
Available in English, per the latest NCERT syllabus for 2023–24 & 2025- 2026
